How to Enumerate an Enum With String Type

How to enumerate an enum with String type?

Swift 4.2+

Starting with Swift 4.2 (with Xcode 10), just add protocol conformance to CaseIterable to benefit from allCases. To add this protocol conformance, you simply need to write somewhere:

extension Suit: CaseIterable {}

If the enum is your own, you may specify the conformance directly in the declaration:

enum Suit: String, CaseIterable { case spades = "♠"; case hearts = "♥"; case diamonds = "♦"; case clubs = "♣" }

Then the following code will print all possible values:

Suit.allCases.forEach {
    print($0.rawValue)
}

---

Compatibility with earlier Swift versions (3.x and 4.x)

If you need to support Swift 3.x or 4.0, you may mimic the Swift 4.2 implementation by adding the following code:

#if !swift(>=4.2)
public protocol CaseIterable {
    associatedtype AllCases: Collection where AllCases.Element == Self
    static var allCases: AllCases { get }
}
extension CaseIterable where Self: Hashable {
    static var allCases: [Self] {
        return [Self](AnySequence { () -> AnyIterator<Self> in
            var raw = 0
            var first: Self?
            return AnyIterator {
                let current = withUnsafeBytes(of: &raw) { $0.load(as: Self.self) }
                if raw == 0 {
                    first = current
                } else if current == first {
                    return nil
                }
                raw += 1
                return current
            }
        })
    }
}
#endif

How to enumerate an enum with String type?

Swift 4.2+

Starting with Swift 4.2 (with Xcode 10), just add protocol conformance to CaseIterable to benefit from allCases. To add this protocol conformance, you simply need to write somewhere:

extension Suit: CaseIterable {}

If the enum is your own, you may specify the conformance directly in the declaration:

enum Suit: String, CaseIterable { case spades = "♠"; case hearts = "♥"; case diamonds = "♦"; case clubs = "♣" }

Then the following code will print all possible values:

Suit.allCases.forEach {
    print($0.rawValue)
}

---

Compatibility with earlier Swift versions (3.x and 4.x)

If you need to support Swift 3.x or 4.0, you may mimic the Swift 4.2 implementation by adding the following code:

#if !swift(>=4.2)
public protocol CaseIterable {
    associatedtype AllCases: Collection where AllCases.Element == Self
    static var allCases: AllCases { get }
}
extension CaseIterable where Self: Hashable {
    static var allCases: [Self] {
        return [Self](AnySequence { () -> AnyIterator<Self> in
            var raw = 0
            var first: Self?
            return AnyIterator {
                let current = withUnsafeBytes(of: &raw) { $0.load(as: Self.self) }
                if raw == 0 {
                    first = current
                } else if current == first {
                    return nil
                }
                raw += 1
                return current
            }
        })
    }
}
#endif

How to enumerate an enum

foreach (Suit suit in (Suit[]) Enum.GetValues(typeof(Suit)))
{
}

Note: The cast to (Suit[]) is not strictly necessary, but it does make the code 0.5 ns faster.

TypeScript iterate over string enum with the enum type instead of string type

I'll post my comments as an answer so the questions won't remain unanswered.

The type of cipher will have the keys as the values of Enum, that is:

let cipher: {
  a: string;
  b: string;
}

because you are using a string enum. But when iterating with for...in you iterate over the enumerable properties of the generated object, those properties are ['A', 'B'] because the generated object(TypeScript v4) would be:

var Enum;
(function (Enum) {
    Enum["A"] = "a";
    Enum["B"] = "b";
})(Enum || (Enum = {}));

So you need to iterate over the enum values.
For this you can use Object.values to get an array of it's values and for...of to iterate over it. This way, letter type will be Enum.

for (const letter of Object.values(Enum)) {
    cipher[letter] = 'test'; // error: letter is of type 'string' but needs to be 'Enum'
}

I never used for...in with an enum before but I would have expected the compiler to have enough information so the for...in strictly types letter to a union of "A" | "B" but it seems that it widens the type to string.

Iterate on string enum

@Artem and @betadeveloper pointed out that I can use the keyof typeof Locales type for my approach. The solution I eventually came up with looks like this:

const keys: (keyof typeof Locales)[] = <(keyof typeof Locales)[]>Object.keys(Locales);
for (const key of keys) {
  const locale: string = Locales[key];
  console.log(locale); // Prints 'en', 'fr' and so on
}

Enum from String

Using mirrors you could force some behaviour. I had two ideas in mind. Unfortunately Dart does not support typed functions:

import 'dart:mirrors';

enum Visibility {VISIBLE, COLLAPSED, HIDDEN}

class EnumFromString<T> {
  T get(String value) {
    return (reflectType(T) as ClassMirror).getField(#values).reflectee.firstWhere((e)=>e.toString().split('.')[1].toUpperCase()==value.toUpperCase());
  }
}

dynamic enumFromString(String value, t) {
  return (reflectType(t) as ClassMirror).getField(#values).reflectee.firstWhere((e)=>e.toString().split('.')[1].toUpperCase()==value.toUpperCase());
}

void main() {
  var converter = new EnumFromString<Visibility>();

  Visibility x = converter.get('COLLAPSED');
  print(x);

  Visibility y = enumFromString('HIDDEN', Visibility);
  print(y);
}

Outputs:

Visibility.COLLAPSED
Visibility.HIDDEN

How to define an enum with string value?

You can't - enum values have to be integral values. You can either use attributes to associate a string value with each enum value, or in this case if every separator is a single character you could just use the char value:

enum Separator
{
    Comma = ',',
    Tab = '\t',
    Space = ' '
}

(EDIT: Just to clarify, you can't make char the underlying type of the enum, but you can use char constants to assign the integral value corresponding to each enum value. The underlying type of the above enum is int.)

Then an extension method if you need one:

public string ToSeparatorString(this Separator separator)
{
    // TODO: validation
    return ((char) separator).ToString();
}

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