Tsql Strip Date from Datetime

TSQL strip date from datetime

Try the TimeOnly function from Essential SQL Server Date, Time, and DateTime Functions:

create function TimeOnly(@DateTime DateTime)
returns datetime
as
    begin
    return dateadd(day, -datediff(day, 0, @datetime), @datetime)
    end
go

Or simply cast the DateTime as Time in SQL Server 2008:

declare @time as time
set @time = cast(dateTimeVal as time)

Best approach to remove time part of datetime in SQL Server

Strictly, method a is the least resource intensive:

a) select DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)

Proven less CPU intensive for the same total duration a million rows by someone with way too much time on their hands: Most efficient way in SQL Server to get a date from date+time?

I saw a similar test elsewhere with similar results too.

I prefer the DATEADD/DATEDIFF because:

• varchar is subject to language/dateformat issues
  
  Example: Why is my CASE expression non-deterministic?
• float relies on internal storage
• it extends to work out first day of month, tomorrow, etc by changing "0" base

Edit, Oct 2011

For SQL Server 2008+, you can CAST to date i.e. CAST(getdate() AS date). Or just use date datatype so no time to remove.

Edit, Jan 2012

A worked example of how flexible this is: Need to calculate by rounded time or date figure in sql server

Edit, May 2012

Do not use this in WHERE clauses and the like without thinking: adding a function or CAST to a column invalidates index usage. See number 2 here Common SQL Programming Mistakes

Now, this does have an example of later SQL Server optimiser versions managing CAST to date correctly, but generally it will be a bad idea ...

Edit, Sep 2018, for datetime2

DECLARE @datetime2value datetime2 = '02180912 11:45' --this is deliberately within datetime2, year 0218
DECLARE @datetime2epoch datetime2 = '19000101'

select DATEADD(dd, DATEDIFF(dd, @datetime2epoch, @datetime2value), @datetime2epoch)

How do I strip the date off of a datetime string in SQL SSIS?

I would just do a cast to DT_DBTIME type (using Derived Column transform, or Convert type transform). DT_DBTIME contains just (hours, minutes, seconds) part of the date/time, so you'll get rid of the date part.

How to return only the Date from a SQL Server DateTime datatype

SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, @your_date))

for example

SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))

gives me

2008-09-22 00:00:00.000

Pros:

• No varchar<->datetime conversions required
• No need to think about locale

SQL Server remove milliseconds from datetime

You just have to figure out the millisecond part of the date and subtract it out before comparison, like this:

select * 
from table 
where DATEADD(ms, -DATEPART(ms, date), date) > '2010-07-20 03:21:52'

Extract date from datetime column - SQL Server Compact

SQL Server Compact has no date type.

If you don't want to see the time, convert the datetime value to a string:

SELECT CONVERT(nvarchar(10), GETDATE(), 120)

(This has been tested and actually works against SQL Server Compact)

Convert a SQL Server datetime to a shorter date format

Have a look at CONVERT. The 3rd parameter is the date time style you want to convert to.

e.g.

SELECT CONVERT(VARCHAR(10), GETDATE(), 103) -- dd/MM/yyyy format

How to convert datetime to date only (with time set to 00:00:00.000)

For SQL Server 2005 and below:

CONVERT(varchar(8), @ParamDate, 112)    -- Supported way

CAST(FLOOR(CAST(@ParamDate AS float)) AS DATETIME)   -- Unsupported way

For SQL Server 2008 and above:

CAST(@ParamDate AS DATE)

Time part of a DateTime Field in SQL

In SQL Server if you need only the hh:mi, you can use:

DECLARE @datetime datetime

SELECT @datetime = GETDATE()

SELECT RIGHT('0'+CAST(DATEPART(hour, @datetime) as varchar(2)),2) + ':' +
       RIGHT('0'+CAST(DATEPART(minute, @datetime)as varchar(2)),2)

Remove time from DateTime sql server 2005

SELECT CONVERT(VARCHAR(10),GETDATE(),105)

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