MySQL Multiple Joins in one query?
You can simply add another join like this:
SELECT dashboard_data.headline, dashboard_data.message, dashboard_messages.image_id, images.filename
FROM dashboard_data
INNER JOIN dashboard_messages
ON dashboard_message_id = dashboard_messages.id
INNER JOIN images
ON dashboard_messages.image_id = images.image_id
However be aware that, because it is an INNER JOIN
, if you have a message without an image, the entire row will be skipped. If this is a possibility, you may want to do a LEFT OUTER JOIN
which will return all your dashboard messages and an image_filename only if one exists (otherwise you'll get a null)
SELECT dashboard_data.headline, dashboard_data.message, dashboard_messages.image_id, images.filename
FROM dashboard_data
INNER JOIN dashboard_messages
ON dashboard_message_id = dashboard_messages.id
LEFT OUTER JOIN images
ON dashboard_messages.image_id = images.image_id
SQL Multiple INNER JOINS In One Select-Statement
You want to summarize across different "dimensions" -- that is tables. One good approach is to aggregate before doing the JOIN
s. Or to use subqueries. Here is the latter approach:
SELECT pm.prod_id, pm.prod_name,
(SELECT SUM(ed.prod_qty)
FROM estimatedetailstb as ed
WHERE ed.prodid = ed.prodidas
) as Est_qty,
(SELECT SUM(sd.prod_qty)
FROM salesdetailstb as sd
WHERE sd.prodid = pm.prodidas
) as Sales_qty,
(SELECT SUM(pd.prod_qty)
FROM purchasedetailstb as pd
WHERE pd.prodid = pm.prodid
) as Sales_qty
FROM productmaster pm;
This will give you all products, even those missing from one or more of the other tables.
SQL multiple join statement
For multi-table joins, you have to nest the extra joins in brackets:
SELECT ...
FROM ((origintable
JOIN jointable1 ON ...)
JOIN jointable2 ON ...)
JOIN jointable3 ON ...
basically, for every extra table you join past the first, you need a bracket before the original 'FROM' table, and a closing bracket on the matching JOIN 'on' clause.
case statement in sql with multiple joins
A simpler approach
select a, b, table_one.c, d, e
, table_three.other_column is not null as flag
from table_one inner join table_two on table_one.d = table_two.c
left join table_three on -- put here the relation rules between table_three
-- and the other tables
Case Statement With Multiple Joins
I think the most direct way to represent what you're asking for is:
select coalesce(l2.city, l1.city, '0') as city
From emp r
left join location l1
on l1.eid = r.eid
and l1.type=1
left join location l2
on l2.eid = r.eid
and l2.type=2
The subquery-based solution proposed by Jeremy Real may also work, but it assumes that 1 and 2 are they only values in the table for location.type
(and I just don't find it to be as intuitive).
SQL query with multiple joins (And Exists?)
You will want to add a NOT EXISTS
clause to your query, and remove the LEFT JOIN
to your ConditionalCheck table, since you're not actually doing anything with the data there:
Select A.Column1, A.Column2, B.Column1, IsNull(D.Column1, '')
From User A With (NoLock)
Inner Join UserDetails B With (NoLock) On (B.id = A.id)
Left Join UserData C With (NoLock) On (C.uid = B.uid)
Left Join MoreData D With (NoLock) On (D.id = A.id)
Where A.Column1 = 'ABC'
And Not Exists
(
Select *
From ConditionalCheck CC
Where CC.S_id = B.S_id
And CC.T_id In (2,3)
)
As a side note, for the context of the query provided, the LEFT JOIN
to the UserData table is also unnecessary.
IBM DB2: SQL query with multiple Join
The issue is probably due to the below clause:
INNER JOIN ICMADMIN.table_002 ON INDEX_NOREL = A.INDEX_NOREL
Here INDEX_NOREL
on the left side is not accompanied by any table alias. Since ICMADMIN.table_001
and ICMADMIN.table_002
both have the column named INDEX_NOREL
, that is why you are facing this issue. Just create an alias for ICMADMIN.table_002
and accompany INDEX_NOREL
by that alias it will work.
FROM ICMADMIN.table_001 A
INNER JOIN ICMADMIN.table_002 C ON C.INDEX_NOREL = A.INDEX_NOREL
presto sql: multiple join with `using` statement
Your two versions are functionally equivalent (except for the obvious difference of a duplicated user_id
column when not using using
). The first inner join
mandates that the two user_id
s have the same value, so either comparison returns the same result set.
If you had a series of left join
s then you would be requiring that the value be in the first table, and the equivalent would be t1.user_id
.
If you had full join
s, then you would not know. The matching would be from the table that has a value on the row. If both tables have a value, the logic says that they are the same, so it doesn't make a difference.
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