How to Select Rows With Max(Column Value), Partition by Another Column in MySQL

How can I SELECT rows with MAX(Column value), PARTITION by another column in MYSQL?

You are so close! All you need to do is select BOTH the home and its max date time, then join back to the topten table on BOTH fields:

SELECT tt.*
FROM topten tt
INNER JOIN
    (SELECT home, MAX(datetime) AS MaxDateTime
    FROM topten
    GROUP BY home) groupedtt 
ON tt.home = groupedtt.home 
AND tt.datetime = groupedtt.MaxDateTime

SQL : Keep ONE row with max value on a column depending on value of another column

One method is rank() or row_number();

select t.*
from (select t.*,
             row_number() over (partition by id order by col1 desc, col2 asc) as seqnum
      from t
     ) t
where seqnum = 1;

You would use rank() if you want multiple rows when there are duplicate max col1/ min col2 for the same id.

Select rows with Max(Column Value) for each unique combination of two other columns

In MySQL 5.x you can use a sub-query.

SELECT * 
FROM your_table
WHERE (`Group`, Dataset, RunNumber) IN (
    SELECT `Group`, Dataset, MAX(RunNumber) AS MaxRunNumber
    FROM your_table
    GROUP BY `Group`, Dataset
  );

Test on db<>fiddle here

Alternatives

--
-- LEFT JOIN on bigger
--
SELECT t.* 
FROM your_table t
LEFT JOIN your_table t2
  ON t2.`Group` = t.`Group`
 AND t2.Dataset = t.Dataset
 AND t2.RunNumber > t.RunNumber
WHERE t2.RunNumber IS NULL
ORDER BY t.`Group`, t.Dataset;

--
-- where NOT EXISTS on bigger
--
SELECT * 
FROM your_table t
WHERE NOT EXISTS (
  SELECT 1
  FROM your_table t2
  WHERE t2.`Group` = t.`Group`
    AND t2.Dataset = t.Dataset
    AND t2.RunNumber > t.RunNumber
)
ORDER BY `Group`, Dataset;

--
-- Emulating DENSE_RANK = 1 with variables
-- Works also in 5.x
--
SELECT RunNumber, `Group`, Dataset, Total
FROM
(
  SELECT 
    @rnk:=IF(@ds=Dataset AND @grp=`Group`, IF(@run=RunNumber, @rnk, @rnk+1), 1) AS Rnk
  , @grp := `Group` as `Group`
  , @ds := Dataset as Dataset
  , @run := RunNumber as RunNumber
  , Total
  FROM your_table t
  CROSS JOIN (SELECT @grp:=null, @ds:=null, @run:=null, @rnk := 0) var
  ORDER BY `Group`, Dataset, RunNumber DESC
) q
WHERE Rnk = 1
ORDER BY `Group`, Dataset;

--
-- DENSE_RANK = 1
-- MySql 8 and beyond. 
--
SELECT *
FROM
(
  SELECT *
  , DENSE_RANK() OVER (PARTITION BY `Group`, Dataset ORDER BY RunNumber DESC) AS rnk
  FROM your_table
) q
WHERE rnk = 1
ORDER BY `Group`, Dataset;

SQL select only rows with max value on a column

At first glance...

All you need is a GROUP BY clause with the MAX aggregate function:

SELECT id, MAX(rev)
FROM YourTable
GROUP BY id

It's never that simple, is it?

I just noticed you need the content column as well.

This is a very common question in SQL: find the whole data for the row with some max value in a column per some group identifier. I heard that a lot during my career. Actually, it was one the questions I answered in my current job's technical interview.

It is, actually, so common that Stack Overflow community has created a single tag just to deal with questions like that: greatest-n-per-group.

Basically, you have two approaches to solve that problem:

Joining with simple group-identifier, max-value-in-group Sub-query

In this approach, you first find the group-identifier, max-value-in-group (already solved above) in a sub-query. Then you join your table to the sub-query with equality on both group-identifier and max-value-in-group:

SELECT a.id, a.rev, a.contents
FROM YourTable a
INNER JOIN (
    SELECT id, MAX(rev) rev
    FROM YourTable
    GROUP BY id
) b ON a.id = b.id AND a.rev = b.rev

Left Joining with self, tweaking join conditions and filters

In this approach, you left join the table with itself. Equality goes in the group-identifier. Then, 2 smart moves:

1. The second join condition is having left side value less than right value
2. When you do step 1, the row(s) that actually have the max value will have NULL in the right side (it's a LEFT JOIN, remember?). Then, we filter the joined result, showing only the rows where the right side is NULL.

So you end up with:

SELECT a.*
FROM YourTable a
LEFT OUTER JOIN YourTable b
    ON a.id = b.id AND a.rev < b.rev
WHERE b.id IS NULL;

Conclusion

Both approaches bring the exact same result.

If you have two rows with max-value-in-group for group-identifier, both rows will be in the result in both approaches.

Both approaches are SQL ANSI compatible, thus, will work with your favorite RDBMS, regardless of its "flavor".

Both approaches are also performance friendly, however your mileage may vary (RDBMS, DB Structure, Indexes, etc.). So when you pick one approach over the other, benchmark. And make sure you pick the one which make most of sense to you.

Get records with max value for each group of grouped SQL results

There's a super-simple way to do this in mysql:

select * 
from (select * from mytable order by `Group`, age desc, Person) x
group by `Group`

This works because in mysql you're allowed to not aggregate non-group-by columns, in which case mysql just returns the first row. The solution is to first order the data such that for each group the row you want is first, then group by the columns you want the value for.

You avoid complicated subqueries that try to find the max() etc, and also the problems of returning multiple rows when there are more than one with the same maximum value (as the other answers would do)

Note: This is a mysql-only solution. All other databases I know will throw an SQL syntax error with the message "non aggregated columns are not listed in the group by clause" or similar. Because this solution uses undocumented behavior, the more cautious may want to include a test to assert that it remains working should a future version of MySQL change this behavior.

Version 5.7 update:

Since version 5.7, the sql-mode setting includes ONLY_FULL_GROUP_BY by default, so to make this work you must not have this option (edit the option file for the server to remove this setting).

Mysql get latest record/row based on another columns latest/max

In MySQL 8 or later you can use row_number window function:

with cte as (
    select *, row_number() over (partition by ref_id order by version desc) as rn
    from t
)
select *
from t
where rn = 1

For earlier versions of MySQL your existing approach is best but an alternate solution worth trying:

select *
from t
where (ref_id, version) in (
    select ref_id, max(version)
    from t
    group by ref_id
)

Select all rows where maximum value on a one column from two tables with union

As fix_id is unique in both tables, the answer with CASE statements (https://stackoverflow.com/a/65609931/53341) is likely the fastest (so, I've upvoted that)...

• Join once
• Compare rates, on each row
• Pick which table to read from, on each row

For large numbers of columns, however, it's unwieldy to type all the CASE statements. So, here is a shorter version, though it probably takes twice as long to run...

SELECT t1.*
  FROM table1 AS t1 INNER JOIN table2 AS t2 ON t1.fix_id = t2.fix_id
 WHERE t1.rate >= t2.rate

UNION ALL

SELECT t2.*
  FROM table1 AS t1 INNER JOIN table2 AS t2 ON t1.fix_id = t2.fix_id
 WHERE t1.rate <  t2.rate

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