How to in a Query Calculate the Sum of the Union

a simple way to sum a result from UNION in MySql

select id, sum(amount) from (
    select id,amount from table_1 union all
    select id,amount from table_2 union all
    select id,amount from table_3
) x group by id

Sum union values

You can try using this in a subquery and calculate at the outer query. Ensure you use UNION ALL to evade the duplicate check

SELECT SUM(a) target_value
FROM
(SELECT
       sum(target_value) a FROM table
UNION ALL
SELECT 
       sum(target_value) a FROM table_2) ;

SQL Query to sum multiple count union queries

You don't need window functions for that

select sum(cnt) as total
from
(
  SELECT COUNT(col_x) as cnt FROM tablea
  UNION
  SELECT COUNT(col_y) FROM tableb
) tmp

Sum a union query

You need to alias your derived table, you must also use a group by with a having clause.

SELECT
  q1.Period, 
  q1.PCC, 
  SUM(q1.BasicHits), 
  SUM(q1.FareHits), 
  SUM(q1.SearchHits)
FROM (SELECT     
        AAAPeriod AS Period, 
        AAAFromPCC AS PCC, 
        - SUM(AAABasic) AS BasicHits,
        - SUM(AAAFare) AS FareHits,
        - SUM(AAASearch) AS SearchHits
      FROM HitsAaa
      GROUP BY 
        AAAPeriod, 
        AAAFromPCC
      HAVING (AAAPeriod = N'2010-10') 

      UNION ALL

      SELECT     
        AAAPeriod AS Period, 
        AAAtoPCC AS PCC,
        SUM(AAABasic) AS BasicHits,
        SUM(AAAFare) AS FareHits,
        SUM(AAASearch) AS SearchHits 
      FROM HitsAaa
      GROUP BY 
        AAAPeriod, 
        AAAtoPCC
      HAVING (AAAPeriod = N'2010-10')

      UNION ALL

      SELECT
        AgtPeriod AS Period, 
        AgtPcc AS PCC, 
        SUM(AgtBasic) AS BasicHits,
        SUM(AgtFare) AS FareHits,
        SUM(AgtSearch)  AS SearchHits
      FROM HitsAgent
      GROUP BY 
        AgtPeriod, 
        AgtPCC
      HAVING (AgtPeriod = N'2010-10')) q1 
GROUP BY 
  q1.Period, 
  q1.PCC

SQL sum rows in union

You don't actually need to use a UNION for this - you can just add them together manually:

SELECT a.countKey + b.sumOccur as total
FROM (SELECT COUNT(DISINCT clientkey) as countKey
      FROM <table>
      WHERE <conditions>) as a
CROSS JOIN (SELECT SUM(occurrences) as sumOccur
            FROM <table2>
            WHERE <conditions>) as b

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