How to get the numeric part from a string using T-SQL?
select left(@str, patindex('%[^0-9]%', @str+'.') - 1)
Query to get only numbers from a string
First create this
CREATE FUNCTION dbo.udf_GetNumeric
DECLARE @intAlpha INT
SET @intAlpha = PATINDEX('%[^0-9]%', @strAlphaNumeric)
WHILE @intAlpha > 0
SET @strAlphaNumeric = STUFF(@strAlphaNumeric, @intAlpha, 1, '' )
SET @intAlpha = PATINDEX('%[^0-9]%', @strAlphaNumeric )
Now use the
I hope this solved your problem.
SQL take just the numeric values from a varchar
Here's the example with PATINDEX:
select SUBSTRING(fieldName, PATINDEX('%[0-9]%', fieldName), LEN(fieldName))
This assumes (1) the field WILL have a numeric, (2) the numerics are all grouped together, and (3) the numerics don't have any subsequent characters after them.
T-SQL Extract Numbers from a string and everything in between
You can use
select substring(col, patindex('%[0-9]%', col),
len(col) - charindex(' ', col, patindex('%[0-9]%', col)) - 1
) as col
How to extract numbers from a string using TSQL
Since you have stable text and only 2 elements, you can make good use of replace and parsename:
declare @string varchar(100) = 'TEST RESULTS\TEST 1\RESULT 2'
select cast(parsename(replace(replace(@string, 'TEST RESULTS\TEST ', ''), '\RESULT ', '.'), 2) as int) as Test
, cast(parsename(replace(replace(@string, 'TEST RESULTS\TEST ', ''), '\RESULT ', '.'), 1) as int) as Result
The replace portion does assume the same text and spacing always, and sets up for parsename with the period.
SQL How to extract numbers from a string?
Use a combination of
SELECT Substr (textstring, 1,instr(textstring,' ') - 1) AS Output
Use this if you have text at the beginning e.g.
aa12345 devils number is my PIN, that is 6666. as it utilises the
SELECT REGEXP_REPLACE(Substr (textstring, 1,instr(textstring,' ') - 1), '[[:alpha:]]','') AS Output
SQL Fiddle: http://sqlfiddle.com/#!4/8edc9/1/0
Finding out just the numeric part from string and storing it as decimal datatype
If there can be only one such number in a string and if it always starts with a digit (i.e. there are no values omitting the 0 before the decimal like
'.75') and ends with a digit, you can find the first digit by applying
patindex() to the string (as you already do) and the last digit by applying
patindex() to the
reverse() of the string.
SELECT convert(decimal(3, 1),
+ 2)) new_value
SQL: Extract numbers from string using Patindex-function
According to your sample data and expected results, you can get it with some relatively simple expressions.
SUBSTRING( A, 0, ISNULL(NULLIF(PATINDEX('%[0-9]%', A), 0), LEN(A)+1)),
SUBSTRING( A, NULLIF(PATINDEX('%[0-9]%', A), 0), LEN(A))
For the first column, I start with 0 to avoid substracting 1 to the first digit position. I then use a combination of
ISNULL(NULLIF(,0)LEN(A)) to assign the total length in case there are no digits available.
For the second columns, I still use
NULLIF, but I don't use
ISNULL to keep the value as NULL. I then just add the total length of the string.
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