Error: Column of Relation Does Not Exist Postgresql ,Unable to Run Insert Query

ERROR: column of relation does not exist PostgreSQL ,Unable to run insert query

If you define the columns with double quotes, then you generally need to use them when you refer to the column:

insert into tester3 ("UN0", "UN1")
     values ( 1, 'jishnu1');

I would suggest you remove the double quotes from the column names in the CREATE TABLE statement.

You don't need the double quotes if the name is all lower case.

Postgresql column exists, but getting column of relation does not exist

If you have table names with upper case you have to enclose the table with double quotes

insert into messages( "replyDate") values('2021-05-07T11:33:36.721Z'),('2021-05-07T11:33:39.704Z'),('2021-05-07T11:33:42.414Z'),('2021-05-07T11:33:42.422Z'),('2021-05-07T11:33:49.454Z')

PGError: Error: column of relation does not exist

If you are sure that column isGroup exists, then you should quote it like:

UPDATE posts SET "isGroup" = 'public'

Note that PostgreSQL by default folds all unquoted named to lowercase.

To avoid this confusion and necessity to quote, you might want to rename isGroup to isgroup using ALTER TABLE ... RENAME COLUMN ....

Postgresql Column Doesn't Exist

if you really have a camel case in you column name then you must wrap the column name with double quote

SELECT "CntrctTrmntnInd"  FROM return_part_i LIMIT 10;

PostgreSQL columns (object) name are case sensitive when specified with double quotes. Unquoted identifiers are automatically used as lowercase so the correct case sequence must be write with double quotes

and as correctly suggested by Raymond Nijland if you want a LIMIT in result you should use an order by

SELECT "CntrctTrmntnInd"  FROM return_part_i ORDER BY "CntrctTrmntnInd" LIMIT 10;

Postgresql tables exists, but getting relation does not exist when querying

You have to include the schema if isnt a public one

SELECT *
FROM <schema>."my_table"

Or you can change your default schema

SHOW search_path;
SET search_path TO my_schema;

Check your table schema here

SELECT *
FROM information_schema.columns

For example if a table is on the default schema public both this will works ok

SELECT * FROM parroquias_region
SELECT * FROM public.parroquias_region

But sectors need specify the schema

SELECT * FROM map_update.sectores_point

Cannot simply use PostgreSQL table name (relation does not exist)

From what I've read, this error means that you're not referencing the table name correctly. One common reason is that the table is defined with a mixed-case spelling, and you're trying to query it with all lower-case.

In other words, the following fails:

CREATE TABLE "SF_Bands" ( ... );

SELECT * FROM sf_bands;  -- ERROR!

Use double-quotes to delimit identifiers so you can use the specific mixed-case spelling as the table is defined.

SELECT * FROM "SF_Bands";

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Re your comment, you can add a schema to the "search_path" so that when you reference a table name without qualifying its schema, the query will match that table name by checked each schema in order. Just like PATH in the shell or include_path in PHP, etc. You can check your current schema search path:

SHOW search_path
  "$user",public

You can change your schema search path:

SET search_path TO showfinder,public;

See also http://www.postgresql.org/docs/8.3/static/ddl-schemas.html

PostgreSQL trigger error: 'column t of relation inventory_product does not exist'

Don't use the target's table alias on the left hand side of the SET assignment. It's always clear which table is meant there. Btw: the function language is an identifier and should not be quoted:

CREATE OR REPLACE FUNCTION update_inventory()
RETURNS TRIGGER AS $$
BEGIN
  IF NEW.product_id IS NOT NULL THEN
    UPDATE inventory_product AS t
       SET qty = t.qty - NEW.qty
       -- ^ here
    WHERE t.id = NEW.product_id;
  END IF;
END; $$ LANGUAGE plpgsql;

In fact, you don't need any alias at all in the UPDATE statement:

CREATE OR REPLACE FUNCTION update_inventory()
RETURNS TRIGGER AS $$
BEGIN
  IF NEW.product_id IS NOT NULL THEN
    UPDATE inventory_product 
       SET qty = qty - NEW.qty
    WHERE id = NEW.product_id;
  END IF;
END; $$ LANGUAGE plpgsql;

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