One Line If Statement Not Working

One line if statement not working

Remove if from if @item.rigged ? "Yes" : "No"

Ternary operator has form condition ? if_true : if_false

Putting a simple if-then-else statement on one line

That's more specifically a ternary operator expression than an if-then, here's the python syntax

value_when_true if condition else value_when_false

Better Example: (thanks Mr. Burns)

'Yes' if fruit == 'Apple' else 'No'

Now with assignment and contrast with if syntax

fruit = 'Apple'
isApple = True if fruit == 'Apple' else False

vs

fruit = 'Apple'
isApple = False
if fruit == 'Apple' : isApple = True

One line if else statement refuses to work

You have to provide else clause as well for this one liner. Following line will work:

print(BDF) if header is 1 else None

Java one line if does not work for prints

condition ? System.out.println("true") : System.out.println("false");
is not a statement.

From here:

In computer science, a ternary operator is an operator that takes three arguments.

System.out.println("true") does not qualify to be an argument, as the method println() is of void type. Hence, it is not a statement.

Use this instead:

System.out.println(condition ? "true" : "false");

Python: Why if-else oneline statement does not work with continue in else?

Because continue is a statement, not an expression.

x = foo if bar else baz

is meant to produce a value and then bind x to that value. For that to be possible, foo, bar and baz need to be things that can be evaluated (expressions).

What should x become in the case of

x = foo if False else continue?

Right...

Single line if statement in reduce statement not working

The main reason it's not working is because your ternary operation returns a number in both scenarios. .push() returns the length of the array and not the array itself.

So you can change it to use concat:

const arr = [ 'tasselled', 'black', 'low-top', 'lace-up' ]const output = arr.reduce((a,e,i) => e.includes('lace') ? a.concat(i) : a, []);
console.log(output)

One line if/else in JavaScript

You want a ternary operator:

properties['Value'] = (IsItMuted === true) ? 'On' : 'Off';

The ? : is called a ternary operator and acts just like an if/else when used in an expression.

Javascript one line If...else...else if statement

Sure, you can do nested ternary operators but they are hard to read.

var variable = (condition) ? (true block) : ((condition2) ? (true block2) : (else block2))

if statement in R can only have one line?

To be precise, this is not about lines but about statements. You can have the whole if else statement in one line:

> if (TRUE) 1 else 3
[1] 1

A statement will end at the end of the line (if complete), you can see that nicely in interactive mode if you enter the code line by line:

> if (TRUE) 
+ 1
[1] 1
> else
Fehler: Unerwartete(s) 'else' in "else" # error: unexpected 'else' in "else"
> 3
[1] 3

if can come in form if (condition) statement or if (condition) statement else other.statement, the interpreter assumes the first version is meant if the statement is complete after line 2 - in interactive mode it cannot sensibly wait whether an else appears next. This is different in sourced code - there it is clear with the next line which form it is.

Semicolons end statements as well:

> if (TRUE) 1; else 3
[1] 1
Fehler: Unerwartete(s) 'else' in " else" # error: unexpected 'else' in "else"

But you can only have one statement in each branch of the condition.

> if (TRUE) 1; 2 else 3
[1] 1
Fehler: Unerwartete(s) 'else' in " 2 else" # error: unexpected 'else' in "2 else"

Curly braces group statements so they appear as one statement.

> if (TRUE) {1; 2} else 3
[1] 2


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