How to Parse a Url and Extract the Required Substring

How to parse a URL and extract the required substring

I'd do it this way:

require 'uri'

uri = URI.parse('http://something.example.com/directory/')
uri.host.split('.').first
=> "something"

URI is built into Ruby. It's not the most full-featured but it's plenty capable of doing this task for most URLs. If you have IRIs then look at Addressable::URI.

How to extract the Substring from URL present in JSON response using JMeter

You don't need to use complex Beanshell coding, You can do this easily using - Regular Expression Extractor.

Here the example:-

You can see required value extracted and stored in variable name give in Regular expression extractor:

To understand try out reg-ex, you can use https://regex101.com/

Extract strings from user input URL Angular

Since the structure of the input url will always be of that form, You can simply do:

url = "https://www.website.com/shop/SHOPNAME/location/LOCATION"
var subString = url.split( '/' );
var shopName = subString[4];
var shopLocation = subString[6];

Java extract substring from url string

First of all, uri.getPath() returns the path component, but what you're looking for is after the ?, so what you might want to try instead is uri.getQuery().

As for the matching:

Pattern p = Pattern.compile("id=(.+?)-");
Matcher m = p.matcher(uri.getQuery());
if (m.find()) {
    System.out.println(m.group(1));
}

Not tested, but I think it should work. The (.+?) is a capturing group that tries to match characters between the id= and the -.

Find out substring from url/value of a key from url

PySpark:

df \
  .withColumn("partialURL", split("url", "tag=")[1]) \
  .withColumn("tag", split("partialURL", "&")[0]) \
  .drop("partialURL")

How to get a string of characters from the url

There are two ways to approach this:

• Use text pattern matching to extract the string between "reportUUID=" and the following "&". For example you could do this with Pattern and Matcher.

• Use a URL parser to parse the URL. Then either

  • extract the "query" part and use String::split or pattern matching to extract the query parameter you want, or

  • use a 3rd-party library to do the job. Some examples are given in Parse a URI String into Name-Value Collection.

The second approach is better. The problem with the first one is that there are various ways that a URL's query part could be encoded that are liable to confound simple-minded pattern matching. A URL parser will deal with the decoding for you.

Regex for extracting substring in href

Change your regex like below.

href="\/[^"]*\/(.*?)\/"

DEMO

[^"]* negated character class which matches any character but not of double quotes zero or more times.

Extract a part from URL in Javascript

try with this

var url = 'http://a.long.url/can/be/here/jquery.min.js?207';
var path = url.split( '/' );
var stripped = "";
for ( i = 0; i < path.length-1; i++ ) {
    if(i>0) stripped += "/";
    stripped += path[i];
}
alert(stripped)

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