Generate Array of All Letters and Digits

Generate array of all letters and digits

[*('a'..'z'), *('0'..'9')] # doesn't work in Ruby 1.8

or

('a'..'z').to_a + ('0'..'9').to_a

or

(0...36).map{ |i| i.to_s 36 }

(the Integer#to_s method converts a number to a string representing it in a desired numeral system)

Better way to generate array of all letters in the alphabet

I think that this ends up a little cleaner, you don't have to deal with the subtraction and indexing:

char[] alphabet = "abcdefghijklmnopqrstuvwxyz".toCharArray();

Generating an array of letters in the alphabet

I don't think there is a built in way, but I think the easiest would be

  char[] alpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();

ruby - How can I generate an array of every combination of letters and numbers of a given length?

alphanum = [*?a..?z, *?0..?9]
length.times.flat_map { |l|
  alphanum.repeated_permutation(l + 1).map(&:join)
}

Note that length > 3 will give you a lot of results.

EDIT: As meagar says, this is very memory-intensive. An Enumerator-based answer (not as pretty, but won't kill your memory):

e = Enumerator.new do |y|
  length.times do |l|
    alphanum.repeated_permutation(l + 1).each do |p|
      y << p.join
    end
  end
end

How to generate a string or array with every non letter or number character?

If you just care about a small restricted subset of possible symbols (e.g. utf 16), your outlined approach is right on and easy to fill in:

let utf16Chars = [...Array(0xFFFF)].map((_, i) => String.fromCharCode(i));
let alphaNumeric = /[a-zA-Z0-9]/;
let symbols = utf16Chars.filter(e => !e.match(alphaNumeric));

console.log(symbols.length);
console.log(symbols.slice(0,100));

How to generate an array of the alphabet?

You can easily make a function to do this for you if you'll need it a lot

function genCharArray(charA, charZ) {
    var a = [], i = charA.charCodeAt(0), j = charZ.charCodeAt(0);
    for (; i <= j; ++i) {
        a.push(String.fromCharCode(i));
    }
    return a;
}
console.log(genCharArray('a', 'z')); // ["a", ..., "z"]

How to get an easier way of generating the alphabet in C++?

Because all characters can be represented in ASCII codes ('a' starts at 97, all ASCII codes are int), you can simply make a loop to do that. For example:

char albet[26];

for (int ch = 'a'; ch <= 'z'; ch++) {
    //do ch-'a' because we start at index 0
    albet[ch-'a'] = ch;
}

and you are done!

How to create an array containing 1...N

If I get what you are after, you want an array of numbers 1..n that you can later loop through.

If this is all you need, can you do this instead?

var foo = new Array(45); // create an empty array with length 45

then when you want to use it... (un-optimized, just for example)

for(var i = 0; i < foo.length; i++){
  document.write('Item: ' + (i + 1) + ' of ' + foo.length + '<br/>'); 
}

e.g. if you don't need to store anything in the array, you just need a container of the right length that you can iterate over... this might be easier.

See it in action here: http://jsfiddle.net/3kcvm/

Make an array with every character on keyboard

This will give characters that are displayable on the screen.

let characters = [];

for (let i=32; i<127; i++)
  characters.push( String.fromCharCode(i) );

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