R Formatting a Date from a Character Mmm Dd, Yyyy to Class Date

Change Date format - Convert to Date Class

A Date class is always shown like "2020-08-27" in R. That's R's standard Date. To reformat it into something different you can use strftime. It assumes a Date class and outputs a character object with your desired format, e.g.

df1$date2
[1] "2020-08-27" "2020-08-28" "2020-08-29"

class(df1$date2)
[1] "Date"

strftime(df1$date2, format="%m/%d/%Y")
[1] "08/27/2020" "08/28/2020" "08/29/2020"

class(strftime(df1$date2, format="%m/%d/%Y"))
[1] "character"

How to convert full date character into mm/dd/yyyy in R?

We need to convert it to Date class and then use format

format(as.Date(dates, "%B %d %Y"), "%m/%d/%Y")
#[1] "08/24/2012"

As the order is month, day, year use mdy from lubridate

library(lubridate)
format(mdy(dates), "%m/%d/%Y")
#[1] "08/24/2012"

It is based on the order, e.g.

ydm("2012 24 August")
#[1] "2012-08-24"

data

dates <- "August 24 2012"

R - Date ddmmyyyy and dd/mm/yyyy in same column

We can use parse_date_time from lubridate.

date = c("22102002", "23122002", "23/12/02", "29/12/03", ""   ,"04/06/04") 
as.Date(lubridate::parse_date_time(date, c('dmY', 'dmy')))
#[1] "2002-10-22" "2002-12-23" "2002-12-23" "2003-12-29" NA "2004-06-04"

How to convert date from mm/dd/YYYY to dd/mm/YYYY in R?

Don't use regex or string manipulation for date-time operations.

Convert to standard date class and then use format to get data in desired format.

format(as.Date('3/28/2020', '%m/%d/%Y'), '%d/%m/%Y')
#[1] "28/03/2020"


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