In R Plotly Subplot Graph, How to Show Only One Legend

In R plotly subplot graph, how to show only one legend?

The above answer results in a minor problem. The legend is only interactive with the first plot. You need to add the legendgroup to the plot_ly function to make the legend interactive with both plots.

library(plotly)
p1 <-
  iris%>%
  group_by(Species)%>%
  plot_ly(x=~Sepal.Length, color= ~Species, legendgroup=~Species)%>%
  add_markers(y= ~Sepal.Width)
p2 <-
  iris%>%
  group_by(Species)%>%
  plot_ly(x=~Sepal.Length, color= ~Species, legendgroup=~Species)%>%
  add_markers(y= ~Sepal.Width, showlegend=F)
subplot(p1,p2)

Single legend for Plotly subplot for line plots created from two data frames in R

This can be achieved by first bringing the data in the right shape which also simplifies the plotting. Simply row bind your dfs e.g. via dplyr::bindrows and you have the variable you need for setting up the legendgroup. Also, your colors don't reflect the variables y and z but the datasets. Try this:

library(dplyr)
library(plotly)

d1 <- data.frame(x = 1:5,
                 y = c(2, 3, 4, 1, 5),
                 z = c(2, 1, 4, 6, 8))

d2 <- data.frame(x = 1:5,
                 y = c(1, 5, 8, 9, 11),
                 z = c(3, 5, 8, 13, 11))

# Bind the dfs
d3 <- bind_rows(list(d1 = d1, d2 = d2), .id = "id")

py <- d3 %>% 
  plot_ly(x = ~x, y = ~y, color = ~id, legendgroup= ~id) %>% 
  add_lines(colors = c("#D55E00", "#56B4E9"))

pz <- d3 %>% 
  plot_ly(x = ~x, y = ~z, color = ~id, legendgroup= ~id) %>% 
  add_lines(colors = c("#D55E00", "#56B4E9"), showlegend = FALSE)

subplot(py, pz) %>% 
  layout(legend=list(title=list(text='<b> Dataset </b>')))

^{Created on 2020-04-10 by the reprex package (v0.3.0)}

Legend near each plot in subplot plot_ly in R

This is not achievable as of yet, as per this. This is far from a perfect hack, but if you wished, something like this may be workable -

Use n to identify the number of unique elements in your colouring variable.

library(plotly)
n <- 3L
clrs <- colorRampPalette(
  c(rgb(r = 198, g = 89, b = 17, maxColorValue = 255), '#267dff', 'black')
)(n)
annotations <- c('setosa', 'versicolor', 'virginica')
y_annotation <- seq(0.4, 0.6, length.out = n)
p1 <-
  iris %>%
  group_by(Species) %>%
  plot_ly(x = ~Sepal.Length, color = ~Species, showlegend = FALSE, colors = clrs) %>%
  add_markers(y= ~Sepal.Width) %>%
  layout(margin = list(r = 100))
for (i in seq_along(annotations)) {
  p1 <- add_annotations(
    p = p1, text = annotations[i], font = list(color = clrs[i]), 
    x = 1.05, y = y_annotation[i], xref = 'paper', yref = 'paper', 
    showarrow = FALSE, xanchor = 'left'
  )
}
p2 <-
  iris%>%
  group_by(Species) %>%
  plot_ly(x = ~Sepal.Length, color = ~Species, showlegend = FALSE, colors = clrs) %>%
  add_markers(y = ~Sepal.Width) %>%
  layout(margin = list(r = 100))
for (i in seq_along(annotations)) {
  p2 <- add_annotations(
    p = p2, text = annotations[i], font = list(color = clrs[i]), 
    x = 1.05, y = y_annotation[i], xref = 'paper', yref = 'paper', 
    showarrow = FALSE, xanchor = 'left'
  )
}
subplot(p1, p2, nrows = 2, shareX = T, shareY = F, titleX = T, titleY = T)

This would result in a plot like below.

Looping through R Plotly with subplot and hiding all legend except one

There are two issues in your code:

1. i is not 1:3 but your current tibble you are iterating through via lapply (see seq_along below).
   That is why you get the warning:

In if (i == 1) { : the condition has length > 1 and only the first
element will be used

2. showlegend needs to be an argument to plot_ly not to layout because subplot always adopts the layout from one of its plots. see ?subplot and its argument which_layout.

layout options found later in the sequence of plots will override
options found earlier in the sequence

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Here is what I think you are after:

library(plotly)
library(dplyr)

tibble_list <- mtcars %>%
  mutate(vs = as.factor(vs)) %>%
  group_split(cyl)

lapply(seq_along(tibble_list), function(i) {
  show_legend <- if (i == 1) {TRUE} else {FALSE}
  plot_ly(
    data = tibble_list[[i]],
    x = ~ gear,
    y = ~ mpg,
    color = ~ vs,
    type = "bar",
    legendgroup = ~ vs,
    showlegend = show_legend
  ) %>% layout(barmode = "stack")
}) %>% subplot(
  nrows = NROW(.),
  shareX = TRUE,
  shareY = TRUE,
  titleX = TRUE,
  titleY = TRUE,
  margin = 0.05,
  which_layout = 1
)

Please find an offical example here.

Avoiding duplicate legends with R plotly subplot results in missing points

Does this help? I think the issue was in the way you had specified size. The attribute marker controls the size of the points.

require(plotly)
set.seed(1)

a <- data.frame(x=1:3, y=1:3)
b <- data.frame(x=(1:3)+.1, y=(1:3)+.1)
xu <- runif(1000, 0, 3)
xn <- (rnorm(1000) + 3) / 2
co <- 'black'
p <- plot_ly()
# attribute 'marker' controls size of points
pa <- add_markers(p, 
                  data=a, x=~x, y=~y, name='j', legendgroup='j',
                  marker = list(size = 5), color=I(co),
                  showlegend=FALSE)

pb <- add_markers(p, 
                  data=b, x=~x, y=~y, name='j', legendgroup='j',
                  marker = list(size = 5), color=I(co),
                  showlegend=TRUE)

pc <- add_histogram(p, x=~xu, name='k', color=I('black'),
                    legendgroup='k', showlegend=FALSE)
pd <- add_histogram(p, x=~xn, name='k', color=I('black'),
                    legendgroup='k', showlegend=TRUE)

plotly::subplot(pa, pb, pc, pd, shareX=TRUE, shareY=FALSE, titleX=TRUE, nrows=4)

Note that mode = 'markers' (note the plural) is not required if you're using add_markers. It is, however, required if you use the more general add_trace.

Using plotly's subplot function with a shared legend, have each group appear only once in the legend

I suggest a solution with a detour via ggplot2. Hope this helps for your purpose.

library(tidyverse)
library(plotly)
df1 <- data.frame(col1 = rep(LETTERS[1:3], each = 4), col2 = rnorm(12), col3 = runif(12), col4 = rep(c("Fred", "Bob"), each = 6))

p <- ggplot(df1, aes(col2, col3)) + geom_point(aes(color = col4)) + facet_wrap("col1")

plotly::ggplotly(p)

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