How to Not Show All Labels on Ggplot Axis

How to not show all labels on ggplot axis?

Is your year column numeric? You can add scale_x_continuous with a breaks argument to specify where the x axis ticks should be. I can't tell what the range of years is in the image, but if it's from 1900 to 2000 (e.g.) you can do something like this:

ggplot(prova, aes(x=year, y=mass..g.)) +
    geom_line(aes(group=1)) +
    scale_x_continuous(breaks=seq(1900, 2000, 10))

Remove all of x axis labels in ggplot

You have to set to element_blank() in theme() elements you need to remove

ggplot(data = diamonds, mapping = aes(x = clarity)) + geom_bar(aes(fill = cut))+
  theme(axis.title.x=element_blank(),
        axis.text.x=element_blank(),
        axis.ticks.x=element_blank())

R: Skip labels in discrete x axis

You can provide function to the breaks argument that can handle special break rules. In the example below, we're choosing all odd breaks by recycling c(TRUE, FALSE) as a subset operation.

library(ggplot2)

ggplot(mpg, aes(class)) +
  geom_bar() +
  scale_x_discrete(breaks = function(x){x[c(TRUE, FALSE)]})

Some more explanation:

The logical index is repeated until it matches the length of the vector it indexes. If the logical index is c(TRUE, FALSE) if will keep repeating this, so it effectively picks up every odd element of the vector x because the length 2 index is repeated.

x <- 1:9

x[c(TRUE, FALSE)]
#> [1] 1 3 5 7 9

So when you make a length 3 index, this will get repeated 3 times.

x[c(TRUE, FALSE, TRUE)]
#> [1] 1 3 4 6 7 9

If you want to replicate what is going on under the hood, here is how you'd do it.

i <- rep_len(c(TRUE, FALSE), length(x))

x[i]
#> [1] 1 3 5 7 9

how to set the attribute for one label not all labels in axis using ggplot2

There are two options to do this. The first one is to use the {ggtext} package to style the label using html tags.

library(ggplot2)
library(ggtext)

df <- data.frame(x = letters[1:5], y = 1:5)

ggplot(df, aes(x, y)) +
  geom_col() +
  scale_x_discrete(
    labels = c("a", "b", "<span style='font-size:16pt'>c</span>", "d", "e")
  ) +
  theme(
    axis.text.x.bottom = element_markdown()
  )

The second option is with vanilla ggplot2, but is discouraged since the internal implementation is not guaranteed to be vectorised such that this will continue to work (as indicated by the warning).

ggplot(df, aes(x, y)) + 
  geom_col() +
  theme(
    axis.text.x.bottom = element_text(size = c(8.8, 8.8, 16, 8.8, 8.8))
  )
#> Warning: Vectorized input to `element_text()` is not officially supported.
#> Results may be unexpected or may change in future versions of ggplot2.

^{Created on 2021-12-29 by the reprex package (v2.0.1)}

Labelling function for y-axis ggplot (How to hide labels for negative breaks)

It's because if isn't vectorized, look at the warning message when running your breaking code above:

Warning message:
In if (x < 0) { :
the condition has length > 1 and only the first element will be used

You should use ifelse to return a vector the size of x.

ggplot(df, aes(date, value))   +
  geom_col() +
  scale_y_continuous(
    limits = c(-3000,3000),
    breaks = c(-2000, -1000, 0,1000,2000),
    labels = function(x) ifelse(x < 0, "", x)
  )

x-axis labels not showing in ggplot

If you wanted to force ggplot to plot every x axis label, you could use scale_x_continous(breaks = 2005:2021) or breaks = df$year

ggplot(df, aes(year, value, color = tenor)) + 
  geom_line(size=0.5) +
  scale_x_continuous(breaks = df$year) +
  geom_point() +
  xlab("year")

Move only some x axis labels down in ggplot

This is how to do it the hard way, if you really want those long ticks

tibble(x = 0:10, y = rnorm(11)) %>%
  ggplot(aes(x,y)) +
  geom_vline(xintercept = seq(2, 10, 4)/10, color = "white", size = 0.5) +
  geom_point() +
  scale_x_continuous(breaks = c(seq(0,10,4)/10, seq(2,10,1))) +
  coord_cartesian(clip = "off", ylim = c(-2, 2)) +
  annotate("text", label = format(seq(2, 10, 4)/10, nsmall = 1),
           x = seq(2, 10, 4)/10, y = -2.4,
           size = 3) +
  annotate("segment", x = seq(2, 10, 4)/10, xend = seq(2, 10, 4)/10,
           y = -2.33, yend = -2.2, size = 0.2) +
  theme(axis.text = element_text(color = "black"))

ggplot2 remove axis label

To remove x-axis labels, you should try to use axis.text.x=element_blank() in the theme()

Removing the x-axis labels:

ggplot(active_clients)  +
  geom_point(aes(as.factor(year_month), value), size = 2, color="deepskyblue4") +
  geom_line(aes(as.factor(year_month), value, group = 1, alpha = 0.5), color = "deepskyblue4") +
  theme_minimal()+
  theme(axis.text.x=element_blank())

ggplot: show all x-axis values (yearmon type)

Here is a suggestion:

Instead of yearmon() I used here dmy function from lubridate and applied it in ggplot with scale_x_date:

library(lubridate)
library(tidyverse)
df3 %>% 
  mutate(`Month B`=dmy(paste("01", as.character(`Month B`)))) %>% 
  ggplot(aes(`Month B`)) +
  geom_line(aes(y = `colA`, colour = "colA")) +
  geom_line(aes(y = `colB`, colour = "colB")) +
  scale_x_date(date_labels="%b %y",date_breaks  ="1 month")+
  theme(axis.text.x = element_text(angle = 90)) + ggtitle("MyTitle")

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