How to Convert a Factor to Integer\Numeric Without Loss of Information

How to convert a factor to integer\numeric without loss of information?

See the Warning section of ?factor:

In particular, as.numeric applied to
a factor is meaningless, and may
happen by implicit coercion. To
transform a factor f to
approximately its original numeric
values, as.numeric(levels(f))[f] is
recommended and slightly more
efficient than
as.numeric(as.character(f)).

The FAQ on R has similar advice.


Why is as.numeric(levels(f))[f] more efficent than as.numeric(as.character(f))?

as.numeric(as.character(f)) is effectively as.numeric(levels(f)[f]), so you are performing the conversion to numeric on length(x) values, rather than on nlevels(x) values. The speed difference will be most apparent for long vectors with few levels. If the values are mostly unique, there won't be much difference in speed. However you do the conversion, this operation is unlikely to be the bottleneck in your code, so don't worry too much about it.


Some timings

library(microbenchmark)
microbenchmark(
as.numeric(levels(f))[f],
as.numeric(levels(f)[f]),
as.numeric(as.character(f)),
paste0(x),
paste(x),
times = 1e5
)
## Unit: microseconds
## expr min lq mean median uq max neval
## as.numeric(levels(f))[f] 3.982 5.120 6.088624 5.405 5.974 1981.418 1e+05
## as.numeric(levels(f)[f]) 5.973 7.111 8.352032 7.396 8.250 4256.380 1e+05
## as.numeric(as.character(f)) 6.827 8.249 9.628264 8.534 9.671 1983.694 1e+05
## paste0(x) 7.964 9.387 11.026351 9.956 10.810 2911.257 1e+05
## paste(x) 7.965 9.387 11.127308 9.956 11.093 2419.458 1e+05

Converting a factor to numeric without losing information R (as.numeric() doesn't seem to work)

First, factor consists of indices and levels. This fact is very very important when you are struggling with factor.

For example,

> z <- factor(letters[c(3, 2, 3, 4)])

# human-friendly display, but internal structure is invisible
> z
[1] c b c d
Levels: b c d

# internal structure of factor
> unclass(z)
[1] 2 1 2 3
attr(,"levels")
[1] "b" "c" "d"

here, z has 4 elements.

The index is 2, 1, 2, 3 in that order.

The level is associated with each index: 1 -> b, 2 -> c, 3 -> d.

Then, as.numeric converts simply the index part of factor into numeric.

as.character handles the index and levels, and generates character vector expressed by its level.

?as.numeric says that Factors are handled by the default method.

how to convert factor levels to integer in r

We can use match with unique elements

library(dplyr)
dat %>%
mutate_all(funs(match(., unique(.))))
# ID Season Year Weekday
#1 1 1 1 1
#2 2 1 2 2
#3 3 2 1 1
#4 4 2 2 3

Convert factor to integer

You can combine the two functions; coerce to characters thence to numerics:

> fac <- factor(c("1","2","1","2"))
> as.numeric(as.character(fac))
[1] 1 2 1 2

Losing information after converting from factor to numeric in R

You have values with commas( ',') which turn into NA when changing to numeric, remove them before converting to numeric.

xdate1$Amount.in.doc..curr. <- as.numeric(gsub(',', '', xdate1$Amount.in.doc..curr.))

Or use parse_number from readr

xdate1$Amount.in.doc..curr. <- readr::parse_number(as.character(xdate1$Amount.in.doc..curr.))


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