Dplyr Mutate with Conditional Values

Can dplyr package be used for conditional mutating?

Use ifelse

df %>%
mutate(g = ifelse(a == 2 | a == 5 | a == 7 | (a == 1 & b == 4), 2,
ifelse(a == 0 | a == 1 | a == 4 | a == 3 | c == 4, 3, NA)))

Added - if_else: Note that in dplyr 0.5 there is an if_else function defined so an alternative would be to replace ifelse with if_else; however, note that since if_else is stricter than ifelse (both legs of the condition must have the same type) so the NA in that case would have to be replaced with NA_real_ .

df %>%
mutate(g = if_else(a == 2 | a == 5 | a == 7 | (a == 1 & b == 4), 2,
if_else(a == 0 | a == 1 | a == 4 | a == 3 | c == 4, 3, NA_real_)))

Added - case_when Since this question was posted dplyr has added case_when so another alternative would be:

df %>% mutate(g = case_when(a == 2 | a == 5 | a == 7 | (a == 1 & b == 4) ~ 2,
a == 0 | a == 1 | a == 4 | a == 3 | c == 4 ~ 3,
TRUE ~ NA_real_))

Added - arithmetic/na_if If the values are numeric and the conditions (except for the default value of NA at the end) are mutually exclusive, as is the case in the question, then we can use an arithmetic expression such that each term is multiplied by the desired result using na_if at the end to replace 0 with NA.

df %>%
mutate(g = 2 * (a == 2 | a == 5 | a == 7 | (a == 1 & b == 4)) +
3 * (a == 0 | a == 1 | a == 4 | a == 3 | c == 4),
g = na_if(g, 0))

dplyr mutate with conditional values

Try this:

myfile %>% mutate(V5 = (V1 == 1 & V2 != 4) + 2 * (V2 == 4 & V3 != 1))

giving:

  V1 V2 V3 V4 V5
1 1 2 3 5 1
2 2 4 4 1 2
3 1 4 1 1 0
4 4 5 1 3 0
5 5 5 5 4 0

or this:

myfile %>% mutate(V5 = ifelse(V1 == 1 & V2 != 4, 1, ifelse(V2 == 4 & V3 != 1, 2, 0)))

giving:

  V1 V2 V3 V4 V5
1 1 2 3 5 1
2 2 4 4 1 2
3 1 4 1 1 0
4 4 5 1 3 0
5 5 5 5 4 0

Note

Suggest you get a better name for your data frame. myfile makes it seem as if it holds a file name.

Above used this input:

myfile <- 
structure(list(V1 = c(1L, 2L, 1L, 4L, 5L), V2 = c(2L, 4L, 4L,
5L, 5L), V3 = c(3L, 4L, 1L, 1L, 5L), V4 = c(5L, 1L, 1L, 3L, 4L
)), .Names = c("V1", "V2", "V3", "V4"), class = "data.frame", row.names = c("1",
"2", "3", "4", "5"))

Update 1 Since originally posted dplyr has changed %.% to %>% so have modified answer accordingly.

Update 2 dplyr now has case_when which provides another solution:

myfile %>% 
mutate(V5 = case_when(V1 == 1 & V2 != 4 ~ 1,
V2 == 4 & V3 != 1 ~ 2,
TRUE ~ 0))

Combine mutate with conditional statement using a formula in r

Here is one potential solution:

library(tidyverse)
df <- read.table(text = " t1 t2 Rg Rg_SE
1 WT Fat 0.6818 0.0962
2 WT FatPC 0.1853 0.1354
3 WT DTD -0.1684 0.1232
4 Fat DefCode NA 0.1608", header = TRUE)

df %>%
mutate(Rg = ifelse((Rg_SE*2) > abs(as.numeric(as.character(Rg))), NA, Rg))
# t1 t2 Rg Rg_SE
#1 WT Fat 0.6818 0.0962
#2 WT FatPC NA 0.1354
#3 WT DTD NA 0.1232
#4 Fat DefCode NA 0.1608

dplyr conditional mutate with ifelse

An option is to insert the * with a regex

library(dplyr)
library(stringr)
df %>%
mutate(across(Kingdom:Genus, ~str_replace(.x, "(Incertae sedis)", "*\\1*")))


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