Converting HH:MM:SS string in .csv to HH:MM:SS vector in R using hms()
Use parse_hms()
rather than as_hms()
How to convert format of time R?
Read ?strptime
you need the format
to be
strptime("01.01.2017 01:00", format="%d.%m.%Y %H:%M")
#[1] "2017-01-01 01:00:00"
If you need output to be in the particular format we can use format
format(strptime("01.01.2017 01:00", format="%d.%m.%Y %H:%M"), "%Y-%m-%d %H:%M")
#[1] "2017-01-01 01:00"
Same would work with as.POSIXct
as.POSIXct("01.01.2017 01:00", format="%d.%m.%Y %H:%M")
Or to ignore specifying formats directly use lubridate::dmy_hm
lubridate::dmy_hm("01.01.2017 01:00")
One thing to note as mentioned by @42- is although they look the same the output of format
is a character value whereas that of as.POSIXct
and strptime
is a datetime value.
Pandas - Converting date column from dd/mm/yy hh:mm:ss to yyyy-mm-dd hh:mm:ss
If you know you will have a consistent format in your column, you can pass this to to_datetime
:
df['sale_date'] = pd.to_datetime(df['sale_date'], format='%d/%m/%y %H:%M:%S')
If your formats aren't necessarily consistent but do have day before month in each case, it may be enough to use dayfirst=True
though this is difficult to say without seeing the data:
df['sale_date'] = pd.to_datetime(df['sale_date'], dayfirst=True)
How to convert String to Date without knowing the format?
You cant!
If you have the date 2010-08-05
then it can be either 5th August 2010, or 8th May 2010 - you need to know the date format (or at least prioritise one format over the over) to tell them apart.
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