Remove Timestamp from Date String in Python

Python- how do I remove timestamp from datetime data throughout the dataframe?

I tried with an example on my own with the help from https://stackoverflow.com/a/47752555/8660907

Cannot remove timestamp in datetime

This approach might work -

import pandas as pd
df = pd.DataFrame({'dates': ['20-Mar-2020', '21-Mar-2020', '22-Mar-2020']})
df
     dates
0  20-Mar-2020
1  21-Mar-2020
2  22-Mar-2020

df['dates'] = pd.to_datetime(df['dates'], format='%d-%b-%Y').dt.date
df
    dates
0  2020-03-20
1  2020-03-21
2  2020-03-22

How to remove timestamp from datetime column in pandas Style Object

This is just a stopgap solution, but you can manually specify the usual %Y-%m-%d display format for your date column as follows:

styled = (df.style
            .applymap(colorFunction, subset=['column3'])
            .format({'Date': '{:%Y-%m-%d}'}))

Example

# Example data
df = pd.DataFrame({'Date': pd.date_range('2020-01-01', 
                                         '2020-01-05', 
                                         freq='d'),
                   'Value': list(range(-2, 3))})

# Example color function
def f(v):
    return 'color: red;' if v < 0 else None

# Unexpected addition of H:M:S to date column
df.style.applymap(f, subset='Value')

# Specify desired date format
df.style.applymap(f, subset='Value').format({'Date': '{:%Y-%m-%d}'}))

Remove time in date format in Python

You can use strftime to convert back in the format you need :

import datetime
s = "20200113"

temp = datetime.datetime.strptime(s, '%Y%m%d')
# 2020-01-13 00:00:00

final = temp.strftime('%Y-%m-%d')
print(final)
# 2020-01-13

Removing the timestamp from a datetime in pandas dataframe

You can do the following:

dfST['timestamp'] = pd.to_datetime(dfST['timestamp'])

to_datetime() will infer the formatting of the date column. You can also pass errors='coerce' if the column contains non-date values.

After completing the above, you'll be able to create a new column containing only date values:

dfST['new_date_column'] = dfST['timestamp'].dt.date

Remove timestamp and url from string python

Maybe:

patterns = [r"\w{3} \w{3} \d{2} \d{2}:\d{2}:\d{2} \d{4}\s*",    #sun aug 19 13:02:10 2018
        r"\w{3}, \d{2} \w{3} \d{4} \d{2}:\d{2}:\d{2} \w{2}\s*", #Sun, 19 Aug 2018 13:02:08 ET
        r":\s*([\da-zA_Z]+\/)+([a-zA-Z0-9\.]+)",                #URL
        r"([a-zA-Z_!]+)[\.!_]\d+:\s*",                          #word[._!]number:>=0space
        r":\d+",
        "[/':,${}\[\]]"                                         #punctuations
        ]

s = mystr

for p in patterns:
    s = re.sub(p,'', s)

s = s.strip()

print(s)

Output:

hello please connect to the local host
hello not able to find the file
Base url for file_transfer is
var1= 
  responseCode = 400 
  responseDate =  
  responseContent = ABC  
Error performing action failed with error code 400

How to remove timestamp from date without converting to character string

Don't divide by 365 as a year does not always have 365 days. Use the MONTHS_BETWEEN function and divide by 12:

Select ca.CUSTOMID,
       ca.SUBMITDATE, 
       pe.DATEARRIVED,
       MONTHS_BETWEEN( ca.SUBMITDATE, pe.DATEARRIVED )/ 12 AS Years_In_Country 
FROM   CURUM.CLASS ca
       LEFT JOIN CURUM.PERSON pe
       ON ca.CUSTOMID = pe.CUSTOMID

db<>fiddle here

How to remove timestamp from date without converting to character string

This question does not make sense. In Oracle, a DATE data type always has year, month, day, hours, minutes and seconds components and a TIMESTAMP data type has the same with optional fractional seconds and time zone components. Also, they are both binary data formats (consisting of 7 bytes for a DATE and 7 bytes for a TIMESTAMP(0) through to 20 bytes for a TIMESTAMP(9) WITH TIME ZONE) and, as such, neither have any format associated with them.

If you want to remove the "time" component from a DATE or a TIMESTAMP then you need to convert them to a different data type that can display formatted date information; that data type would be a string.

So, if you want it to be a DATE or TIMESTAMP data type then it will have a "time" component and if you don't want it to be have a "time" component then it will be a string.

If by "remove" you mean that you want to set the "time" component to midnight then just use the TRUNC function and the value will be cast to a DATE data type where the time components are at midnight. The NLS_DATE_FORMAT of the session you are using may be set to not show the time component of a DATE data type but it will still exist.

If you want to format the value without a time component then use TO_CHAR( your_column, 'YYYY-MM-DD' ) to convert it to a formatted string.

Pandas, removing timestamp from datetime column using dt.date or dt.strftime converts column to dtype: object

IMO there is no issue here:

s = pd.to_datetime(pd.Series(['2021-02-01 00:00:00']))
s
# 0   2021-02-01
# dtype: datetime64[ns]

And indeed, the displayed type is "object":

s.dt.date
# 0    2021-02-01
# dtype: object

But this doesn't mean much, the type is really datetime.date:

type(s.dt.date[0])
# datetime.date

remove timestamp from string that has date & time - c#

If the string is always going to be in the format you showed (date - blank space - time) you could simply do:

String dateTime = "1/15/2017 12:00:00 AM";
int index = dateTime.indexOf(" "); // gets index of first occurrence of blank space, which in this case separates the date from the time.
dateTime = dateTime.subString(0, index);

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