Import Arbitrary Python Source File. (Python 3.3+)

Import arbitrary python source file. (Python 3.3+)

Found a solution from importlib test code.

Using importlib.machinery.SourceFileLoader:

>>> import importlib.machinery
>>> loader = importlib.machinery.SourceFileLoader('a_b', '/tmp/a-b.txt')
>>> mod = loader.load_module()
>>> mod
<module 'a_b' from '/tmp/a-b.txt'>

NOTE: only works in Python 3.3+.

UPDATE Loader.load_module is deprecated since Python 3.4. Use Loader.exec_module instead:

>>> import types
>>> import importlib.machinery
>>> loader = importlib.machinery.SourceFileLoader('a_b', '/tmp/a-b.txt')
>>> mod = types.ModuleType(loader.name)
>>> loader.exec_module(mod)
>>> mod
<module 'a_b'>

---

>>> import importlib.machinery
>>> import importlib.util
>>> loader = importlib.machinery.SourceFileLoader('a_b', '/tmp/a-b.txt')
>>> spec = importlib.util.spec_from_loader(loader.name, loader)
>>> mod = importlib.util.module_from_spec(spec)
>>> loader.exec_module(mod)
>>> mod
<module 'a_b' from '/tmp/a-b.txt'>

Python: Importing arbitrarily named source files using importlib

A solution to a similar question is posted here. Translated to my example:

import importlib.machinery, importlib.util
loader = importlib.machinery.SourceFileLoader('my_module', '/path/to/my_module')
spec = importlib.util.spec_from_loader(loader.name, loader)
my_module = importlib.util.module_from_spec(spec)
loader.exec_module(my_module)

Python 3.4: How to import a module given the full path?

This should work for all python files, regardless of file extension:

import importlib.machinery

modulename = importlib.machinery.SourceFileLoader('modulename','/Path/To/module.py').load_module()

This method was mentioned in the deprecation message in the imp.load_module documentation.

Import arbitrary python source file. (Python 3.3+)

Found a solution from importlib test code.

Using importlib.machinery.SourceFileLoader:

>>> import importlib.machinery
>>> loader = importlib.machinery.SourceFileLoader('a_b', '/tmp/a-b.txt')
>>> mod = loader.load_module()
>>> mod
<module 'a_b' from '/tmp/a-b.txt'>

NOTE: only works in Python 3.3+.

UPDATE Loader.load_module is deprecated since Python 3.4. Use Loader.exec_module instead:

>>> import types
>>> import importlib.machinery
>>> loader = importlib.machinery.SourceFileLoader('a_b', '/tmp/a-b.txt')
>>> mod = types.ModuleType(loader.name)
>>> loader.exec_module(mod)
>>> mod
<module 'a_b'>

---

>>> import importlib.machinery
>>> import importlib.util
>>> loader = importlib.machinery.SourceFileLoader('a_b', '/tmp/a-b.txt')
>>> spec = importlib.util.spec_from_loader(loader.name, loader)
>>> mod = importlib.util.module_from_spec(spec)
>>> loader.exec_module(mod)
>>> mod
<module 'a_b' from '/tmp/a-b.txt'>

How Can I Import A Python 3 Module With A Period In The Filename?

After looking through the CPython quite a lot and coming back to some other solutions (especially Import arbitrary python source file. (Python 3.3+)), I realized that I needed to pass the full path to my module. Here is the cross-platform, call-location-independent solution:

"""

import os, sys # For running from Notepad++ shortcut, etc
import importlib.machinery

program_1_4 = importlib.machinery.SourceFileLoader('program_1.4', os.path.join(sys.path[0], 'program_1.4.py')).load_module()

print(program_1_4)
program_1_4.main()

"""

How do I import a python file through a path?

You need to use importlib to do what you want. Here is an example on how to import my_function from a file:

import importlib
    
spec = importlib.util.spec_from_file_location('some_module_name', filename)
mod = importlib.util.module_from_spec(spec)
spec.loader.exec_module(mod)
mod.my_function(1)

Probably the question is a duplicate of Import arbitrary python source file. (Python 3.3+)

Import Module System (Python Source Code Analysis)

find_and_load function can be found in Lib/importlib/*.py.

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