how to get last column of pandas series
Problem is output of GroupBy.size
is Series
, and Series
have no columns, so is possible get last value only:
b.iloc[-1]
If use:
b.iloc[:,-1]
it return last column in Dataframe
.
Here :
means all rows and -1
in second position last column.
So if create DataFrame
from Series
:
b1 = df.groupby('a').size().reset_index(name='count')
it working like expected.
How to select all but the 3 last columns of a dataframe in Python
Select everything EXCEPT the last 3 columns, do this using iloc
:
In [1639]: df
Out[1639]:
a b c d e
0 1 3 2 2 2
1 2 4 1 1 1
In [1640]: df.iloc[:,:-3]
Out[1640]:
a b
0 1 3
1 2 4
finding last column name when two columns have max value in one row python
what about taking vertical symmetry and then idxmax, i.e.,
df.iloc[:, ::-1].idxmax(axis=1)
0 x
1 z
2 z
3 z
4 y
so the df.iloc[:, ::-1]
part is
z y x
0 0 0 1
1 1 0 1
2 1 0 0
3 1 1 0
4 0 1 1
it's from z to x now
Another way with reindexing might be more clear in giving away the intent:
df.reindex(columns=df.columns[::-1]).idxmax(axis=1)
0 x
1 z
2 z
3 z
4 y
as above.
Read 1st column, 2nd column, and nth column to last column of panda dataframe
If you like to select columns by their numerical index, iloc
is the right thing to use. You can use np.arange
add a range of columns (such as between the 10th to the last one).
import pandas as pd
import numpy as np
cols = [0, 1]
cols.extend(np.arange(10, df.shape[1]))
df.iloc[:,cols]
Alternatively, you can use numpy's r_
slicing trick:
df.iloc[:,np.r_[0:2, 10:df.shape[1]]]
Selecting first n columns and last n columns with pandas
You can use the iloc
function to get the columns, and then pass in the indexes.
df.iloc[:,[0,1,-1,-2]]
How to select some specific solumns and also last column in pandas
Get last column name by indexing:
df = df[['name','age', df.columns[-1]]]
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