stringr: Removing Parentheses and Brackets from string
We can use |
gsub("\\)|\\]", "", Test)
#[1] "-0.158" "0.426" "1.01" "1.6" "2.18" "2.77"
or instead of escaping place the brackets inside the []
gsub("[][()]", "", Test)
#[1] "-0.158" "0.426" "1.01" "1.6" "2.18" "2.77"
If we want to do the extract instead of removing use either gregexpr/regmatches
from base R
or str_extract
from stringr
to check for patterns where a number could start with -
and include .
library(stringr)
str_extract(Test, "-?[0-9.]+")
#[1] "-0.158" "0.426" "1.01" "1.6" "2.18" "2.77"
How to remove parentheses and all data within using Python3
You can try this. r"\((.*?)\)"
The \(
and \)
say we want to target the actual parenthesis.
Then the parenthesis around the expression (.*?)
say that we want to group what is inside.
Finally the .*?
means that we want any character .
and any repetition of that character *?
.
s = "start (inside) this is in between (inside) end"
res = re.sub(r"\((.*?)\)", "", s)
print(res)
prints
'start this is in between end'
Hope that helps.
RegEx remove parentheses from string
Try this regular expression:
s/([()])//g
Brief explanation:[]
is used to create a character set for any regular expression. My character set for this particular case is composed of (
and )
. So overall, substitute (
and )
with an empty string.
Difficulty to remove several parentheses in a string, using stringr, in R
We can use str_remove_all
instead of str_remove
as this matches only the first instance
library(stringr)
str_remove_all(x, "[()]")
#[1] "example"
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