How to get Max output from a while loop
You should add variable (max_amount
) which will store value of money_in_pot
and update it when roll is 7 and current amount more then initial:
import random
count = 0
number = 0
money_in_pot = float(input('Enter amount of money you want to put in pot: '))
max_amount = money_in_pot # store initial value
while money_in_pot > 0:
dice_roll = random.randint(1, 7), random.randint(1, 7)
print(dice_roll)
roll = sum(dice_roll)
count += 1
if roll == 7:
money_in_pot += 4
if money_in_pot > max_amount: # update max if it more then before
max_amount = money_in_pot
print ('You rolled a 7.')
else:
money_in_pot -= 1
print ('You did not roll a 7.')
print ('You are out of money in {} turn/s. Max amount was: {}.'.format(count, max_amount))
Unable to get while loop working to get min and max of numbers
You're comparing strings, so it's doing a lexicographical order, where 6
is larger than 10
. You need to convert the number strings to actual numbers before comparing:
str_num = input("Enter a number: ")
if str_num == "done":
break
num = int(str_num) # Convert to integer
php max value of array in while loop
Many thanks for the ideas here, I got this solved using the following. It may be more convoluted than the answer from @Qirel but there were extra complications I didn't mention as I didn't want to create a mess. For instance these tables are from 2 separate databases which use specific connections and I had to rely on variables as the data in the first table is user created and retrieved based on the value of a cookie.
Thanks to @rpm192, it was almost there.
<?php
$select_table1 = "select * from table1";
$connect_table1 = mysqli_query($con, $select_table1);
while ($row_table1 = mysqli_fetch_array($connect_table1)) {
$type = $row_table1['type'];
$category = $row_table1['category'];
$select_table2 = "select * from table2 where type in('$type') and category in('$category')";
$connect_table2 = mysqli_query($con, $select_table2);
while ($row_table2 = mysqli_fetch_array($connect_table2)) {
$amount = $row_table2['amount'];
$myArray[] = $amount;
}
}
$maxAmount = max($myArray);
echo $maxAmount;
?>
Python Min Max While loop
The output for "code 1" is different from what you expect because the operands in the comparison are str
, for which the defined order is different from the order of the corresponding int
.
In other words, if a
and b
are two int
s such that a > b
, then we can be sure that str(a) > str(b)
only if the length of the two string is the same, otherwise it can happen either str(a) > str(b)
or str(a) < str(b)
depending on the actual value of a
and b
.
The ordering of string consisting of numbers is "alphabetical" on characters appearing first, hence, while "1" < "2" < "3"
, etc., when the two strings have multiple characters, either option is open e.g.:
- for
"2"
and"10"
,"2" > "10"
(opposite of2 < 10
) because"2" > "1"
and the presence of"0"
after the"1"
is irrelevant - for
"2"
and"20"
,"2" < "20"
(same as2 < 20
) because"2" == "2"
and the presence of"0"
after the"2"
in"20"
makes"20"
"bigger".
Note that the string ordering/comparison actually work for any string, even those not containing numbers.
How to find max&min in while loop - c
Printing an int
using a conversion specifier for double
is not a good idea, but invokes the infamous Undefined Behaviour.
The compiler might have noticed you about this. If it didn't, then increase its warning level. For GCC use -Wall -Wextra -pedantic
.
So to fix this either make min
and max
be double
int a = 0, b = 0;
double min = 1000., max = 0.; /* Such initialisations limit your input. */
or leave them be int
(decreasing accuracy), and print them as what there are, namely int
printf("Minimum: %d\nMaximum: %d\n", min, max);
while loop for largest and smallest values Error
removing the else will solve the problem:
int main()
{
int num, minimum=10000000 , max=0;
int choice;
printf(" To Exit Enter (-1)\n");
while(num!=-1)
{
printf(" enter a number: ");
scanf("%d",&num);
if(num>max)
{
max=num;
}
if(num<minimum && num!=-1)
{
minimum=num;
}
}
printf("\n Largest Number: %d \n Smallest number: %d",max,minimum);
}
the problem was that the if condition was always true because you were entering ascending numbers so the else condition was never executed
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