How to Append a List Withoud Adding the Quote

How to append a list withoud adding the quote

Well, I know two possible ways, but the first one is faster:

1:

def add_peer_function():
    all_devices=[item for item in "cisco,linux".split(',')] # or `all_devices = ["cisco", "linux"]`
    print(', '.join(all_devices)) # A prettier way to print list Thanks to Philo

add_peer_function()

2:

def add_peer_function():
    all_devices=[] 
    for item in "cisco,linux".split(','): # or `all_devices = ["cisco", "linux"]`
        all_devices.append(item)

    print(', '.join(all_devices)) # A prettier way to print list Thanks to Philo

add_peer_function()

Python str.split documentation.

Python str.join documentation.

Python list comprehension documentation.

Python Append String inside list just as an element without double quotes

I believe you are confusing putting a list inside a list and concatenating two lists:

[1, 2, paramlist, 5]         # [1, 2, [3, 4], 5]

is not the same as

[1, 2] + paramlist + [5]     # [1, 2, 3, 4, 5]

Instead of using the correct operation you are trying to cast the list to a string to manually remove the square brackets. Needless to say this is the wrong way of doing it.

So i think you are looking for

value4 = [{'PARAMS': ['ProcessingDate=2016-08-29', 'ReRun=Y']}]

paramlist = value4[0]['PARAMS']
paramlist = [elem for x in paramlist for elem in ('-param', x)]
myNewlist = ['Value1', 'value2', 'value3'] + paramlist + ['value5']

print (myNewlist)

which yields

['Value1', 'value2', 'value3', '-param', 'ProcessingDate=2016-08-29', '-param', 'ReRun=Y', 'value5']

Add to python list without quotations

Use ast.literal_eval to parse the string "{'key1': 1, 'key2': 2, 'key3': 3}" to a dictionary.

In [16]: import ast                                                                                                                                                                                     

In [17]: classes = {}                                                                                                                                                                                   

In [18]: classes["class1"] = ast.literal_eval("{'key1': 1, 'key2': 2, 'key3': 3}")                                                                                                                      

In [19]: classes                                                                                                                                                                                        
Out[19]: {'class1': {'key1': 1, 'key2': 2, 'key3': 3}}

Note that you cannot use json.loads here due to the single quotes in your string

In [20]: import json                                                                                                                                                                                    

In [21]: classes = {}                                                                                                                                                                                   

In [22]: classes["class1"] = json.loads("{'key1': 1, 'key2': 2, 'key3': 3}")                                                                                                                            
---------------------------------------------------------------------------
JSONDecodeError                           Traceback (most recent call last)
<ipython-input-22-592615e01642> in <module>
----> 1 classes["class1"] = json.loads("{'key1': 1, 'key2': 2, 'key3': 3}")

JSONDecodeError: Expecting property name enclosed in double quotes: 
line 1 column 2 (char 1)

Prevent outer double quotes in my list

Use ast.literal_eval to convert a string representation of Python data to the actual data structure:

>>> from ast import literal_eval
>>> s = "('x',),('y',)"
>>> literal_eval(s)
(('x',), ('y',))

literal_eval works similarly to eval but can only produce literal Python data from strings: strings, numbers, tuples, lists, dicts, booleans, and None. Quite a bit safer than eval alone.

If you actually want a list vs a tuple from your string:

>>> list(literal_eval(s))
[('x',), ('y',)]

Is it possible to remove all single quotes from a list of strings in python?

If you are looking for datetime, You don't want to use string, Try something like this,

In [12]: import datetime
In [13]: datelist = [datetime.datetime(yearlist[i],monthlist[i],daylist[i]) for i in range(0,j)]

Result

[datetime.datetime(2009, 1, 14, 0, 0), datetime.datetime(2009, 2, 15, 0, 0)]

Removing quotation marks from list items

Try a list comprehension which allows you to effectively and efficiently reassign the list to an equivalent list with quotes removed.

g1 = [i.replace('"', '') for i in g1] # remove quote from each element

How to remove double quotes from list of strings?

Try this:

VERSION = ["'pilot-2'", "'pilot-1'"]
VERSIONS_F = []
for item in VERSION:
  temp = item.replace("'",'')
  VERSIONS_F.append(temp)
print (VERSIONS_F)

it will print ['pilot-2','pilot-1']

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