Horizontal Stacked Bar Plot and Add Labels to Each Section

Stacked Bar Chart with Centered Labels

Why you wrote va="bottom"? You have to use va="center".

Horizontal stacked bar plot and add labels to each section

Edit 2: for more heterogeneous data. (I've left the above method since I find it more usual to work with the same number of records per series)

Answering the two parts of the question:

a) barh returns a container of handles to all the patches that it drew. You can use the coordinates of the patches to aid the text positions.

b) Following these two answers to the question that I noted before (see Horizontal stacked bar chart in Matplotlib), you can stack bar graphs horizontally by setting the 'left' input.

and additionally c) handling data that is less uniform in shape.

Below is one way you could handle data that is less uniform in shape is simply to process each segment independently.

import numpy as np
import matplotlib.pyplot as plt

# some labels for each row
people = ('A','B','C','D','E','F','G','H')
r = len(people)

# how many data points overall (average of 3 per person)
n = r * 3

# which person does each segment belong to?
rows = np.random.randint(0, r, (n,))
# how wide is the segment?
widths = np.random.randint(3,12, n,)
# what label to put on the segment (xrange in py2.7, range for py3)
labels = range(n)
colors ='rgbwmc'

patch_handles = []

fig = plt.figure(figsize=(10,8))
ax = fig.add_subplot(111)

left = np.zeros(r,)
row_counts = np.zeros(r,)

for (r, w, l) in zip(rows, widths, labels):
    print r, w, l
    patch_handles.append(ax.barh(r, w, align='center', left=left[r],
        color=colors[int(row_counts[r]) % len(colors)]))
    left[r] += w
    row_counts[r] += 1
    # we know there is only one patch but could enumerate if expanded
    patch = patch_handles[-1][0] 
    bl = patch.get_xy()
    x = 0.5*patch.get_width() + bl[0]
    y = 0.5*patch.get_height() + bl[1]
    ax.text(x, y, "%d%%" % (l), ha='center',va='center')
  
y_pos = np.arange(8)
ax.set_yticks(y_pos)
ax.set_yticklabels(people)
ax.set_xlabel('Distance')

plt.show()

Which produces a graph like this , with a different number of segments present in each series.

Note that this is not particularly efficient since each segment used an individual call to ax.barh. There may be more efficient methods (e.g. by padding a matrix with zero-width segments or nan values) but this likely to be problem-specific and is a distinct question.

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Edit: updated to answer both parts of the question.

import numpy as np
import matplotlib.pyplot as plt

people = ('A','B','C','D','E','F','G','H')
segments = 4

# generate some multi-dimensional data & arbitrary labels
data = 3 + 10* np.random.rand(segments, len(people))
percentages = (np.random.randint(5,20, (len(people), segments)))
y_pos = np.arange(len(people))

fig = plt.figure(figsize=(10,8))
ax = fig.add_subplot(111)

colors ='rgbwmc'
patch_handles = []
left = np.zeros(len(people)) # left alignment of data starts at zero
for i, d in enumerate(data):
    patch_handles.append(ax.barh(y_pos, d, 
      color=colors[i%len(colors)], align='center', 
      left=left))
    # accumulate the left-hand offsets
    left += d
    
# go through all of the bar segments and annotate
for j in range(len(patch_handles)):
    for i, patch in enumerate(patch_handles[j].get_children()):
        bl = patch.get_xy()
        x = 0.5*patch.get_width() + bl[0]
        y = 0.5*patch.get_height() + bl[1]
        ax.text(x,y, "%d%%" % (percentages[i,j]), ha='center')

ax.set_yticks(y_pos)
ax.set_yticklabels(people)
ax.set_xlabel('Distance')

plt.show()

You can achieve a result along these lines (note: the percentages I used have nothing to do with the bar widths, as the relationship in the example seems unclear):

See Horizontal stacked bar chart in Matplotlib for some ideas on stacking horizontal bar plots.

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Align value labels in horizontal stacked bar plot (Matplotlib)

The factors 1.45 and 2.45 will give the desired result only when the numbers in values1, values2, values3 are all equal.

You need to do the following:

For the second bar, x = first bar value + 0.45 * second bar value

For the third bar, x = first bar value + second bar value + 0.45 * third bar value

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Following is how you can do it.

# Use values1[i] + v * 0.45 as the x-coordinate
for i, v in enumerate(values2):
    plt.text(values1[i] + v * 0.45, i + .145, str(v), color='white', fontweight='bold', fontsize=10, 
             ha='center', va='center')

# Use values1[i] + values2[i] + v * 0.45 as the x-coordinate
for i, v in enumerate(values3):
    plt.text(values1[i] + values2[i] + v * 0.45, i + .145, str(v), color='white', fontweight='bold', fontsize=10, 
             ha='center', va='center')

Adding data labels to a horizontal bar chart in matplotlib

Adding xlabel and ylabel should solve,

plt.xlabel("Cost")
plt.ylabel("Category")

You might also want to create the dataframe:

import pandas as pd
df = {}
df["Category"] = Category
df["Cost"] = Cost
df = pd.DataFrame.from_dict(df)

For adding the data value of each of the bar you can modify your code as follows:

# First make a subplot, so that axes is available containing the function bar_label.
fig, ax = plt.subplots()
g=ax.barh(df['Category'], df['Cost'])
ax.set_xlabel("Cost")
ax.set_ylabel("Category")
ax.bar_label(g, label_type="center") # This provides the labelling, this only available at higher version. You can do pip install -U matplotlib
plt.show()

Reference:

1. Axis Label
2. matplotlib 3.4.2 and above has this

Output:

How to annotate each segment of a stacked bar chart

Imports and DataFrame

import pandas as pd
import matplotlib.pyplot as plt

data = {'var': ['TR', 'AC', 'F&B'], '2019 1Q': [6600, 1256, 588], '2019 2Q': [6566, 1309, 586], '2019 3Q': [7383, 1525, 673]}
df = pd.DataFrame(data)
df.set_index('var', inplace=True)

# display(df)
     2019 1Q  2019 2Q  2019 3Q
var                           
TR      6600     6566     7383
AC      1256     1309     1525
F&B      588      586      673

Update as of matplotlib v3.4.2

• Use matplotlib.pyplot.bar_label
• See How to add value labels on a bar chart for additional details and examples with .bar_label.
• Tested with pandas v1.2.4, which is using matplotlib as the plot engine.

ax = df.T.plot.bar(stacked=True, figsize=(6, 5), rot=0)

for c in ax.containers:
    ax.bar_label(c, label_type='center')
    
ax.legend(title='Categories', bbox_to_anchor=(1.05, 1), loc='upper left')

Original Answer - prior to matplotlib v3.4.2

• Transpose the dataframe and then use pandas.DataFrame.plot.bar with stacked=True.
• An ndarray is returned with one matplotlib.axes.Axes per column with subplots=True.
  
  • In the case of this figure, ax.patches contains 9 matplotlib.patches.Rectangle objects, one for each segment of each bar.
    
    • By using the associated methods for this object, the height, width, x, and y locations can be extracted, and used to annotate the rectangles.
• The difference this question has from How to annotate a stacked bar chart with word count and column name? is the other question needs to extract and use alternate text for labels, and this dataframe needed to be transposed.

ax = df.T.plot.bar(stacked=True)
plt.legend(title='Categories', bbox_to_anchor=(1.05, 1), loc='upper left')

for i, rect in enumerate(ax.patches):
    # Find where everything is located
    height = rect.get_height()
    width = rect.get_width()
    x = rect.get_x()
    y = rect.get_y()

    # The height of the bar is the count value and can used as the label
    label_text = f'{height:.0f}'

    label_x = x + width / 2
    label_y = y + height / 2

    # don't include label if it's equivalently 0
    if height > 0.001:
        ax.text(label_x, label_y, label_text, ha='center', va='center', fontsize=8)

Add Inside Labels to horizontal stacked bar chart chart.js using 'chartjs-plugin-labels'

The following code fixed this:

animation: {
      duration: 1000,
      onComplete() {
        let chartInstance = this.chart;
        let ctx = chartInstance.ctx;
        ctx.textAlign = "end";
        ctx.textBaseline = "middle";
        ctx.fillStyle = "#fff";
        ctx.font = "10px sans-serif";
        this.data.datasets.forEach(function (dataset, i) {
          var label = dataset.label;
          var meta = chartInstance.controller.getDatasetMeta(i);
          meta.data.forEach(function (bar, index) {
            var data = dataset.data[index];
            if (label.indexOf("%") >= 0) data += "%";
            ctx.fillText(data + "%", bar._model.x, bar._model.y);
          });
        });
      },
    },

Can you put labels between horizontal bars?

Using facet:

#fix the order of factors
data3$System <- factor(data3$System, levels = c("Zivildienst", "Katastrophenschutz"))

#plot with facets
ggplot(data3, aes(x = System, y = Anzahl, fill = Einstellung)) +
  geom_bar(stat = "identity") +
  geom_text(aes(y = pos, label = label), size = 4) +
  coord_flip() +
  facet_wrap(vars(System), ncol = 1, scales = "free_y") +
  scale_x_discrete(expand = c(0, 0)) +            # make bar "fuller"
  scale_y_continuous(expand = c(0, 0)) +          # make bar "fuller"
  scale_fill_manual(values = cbPalette) +
  ggtitle("Werden Sie sich für die Alternative entscheiden?", 
          subtitle = "2000 Männer befragt") + 
  theme(panel.background = element_blank(),
        panel.grid.major = element_blank(),
        panel.grid.minor = element_blank(),
        axis.title.y = element_blank(),
        aspect.ratio = .3,
        axis.text.y = element_blank(),
        axis.ticks.y = element_blank(),
        strip.background = element_rect(fill = NA),# remove facet strip background
        strip.text = element_text(hjust = 0)       # left align the facet strip text
        )

How to display data values in stacked horizontal bar chart in Matplotlib

there's a similar question here, just use ax.text and adjust the x and y positioning according to your bar value and bar enumeration, for example:

import pandas as pd
df = pd.DataFrame({'value1':[10, 30, 20],'value2':[20,50,10]})
ax = df.plot.barh(stacked = True);
print(df)
for rowNum,row in df.iterrows():
    xpos = 0
    for val in row:
        xpos += val
        ax.text(xpos + 1, rowNum-0.05, str(val), color='black')
    xpos = 0
display(ax)

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