Get Name of Current Script in Python

Get name of current script in Python

You can use __file__ to get the name of the current file. When used in the main module, this is the name of the script that was originally invoked.

If you want to omit the directory part (which might be present), you can use os.path.basename(__file__).

How do I get the path and name of the file that is currently executing?

p1.py:

execfile("p2.py")

p2.py:

import inspect, os
print (inspect.getfile(inspect.currentframe())) # script filename (usually with path)
print (os.path.dirname(os.path.abspath(inspect.getfile(inspect.currentframe())))) # script directory

get script directory name - Python

import os
os.path.basename(os.path.dirname(os.path.realpath(__file__)))

Broken down:

currentFile = __file__  # May be 'my_script', or './my_script' or
                        # '/home/user/test/my_script.py' depending on exactly how
                        # the script was run/loaded.
realPath = os.path.realpath(currentFile)  # /home/user/test/my_script.py
dirPath = os.path.dirname(realPath)  # /home/user/test
dirName = os.path.basename(dirPath) # test

python how to get a running script's file name in import package

You should be able to use arguments to work it out.

from sys import argv
print(argv[0])

The first argument listed will be the command used to execute your script.
So if you're running ./main.py then that's what you'll get.

If you're running it via python (such as python main.py) then (at least according to my testing) you'll get the full path. You can use the tools in os.path to pluck out just the filename if required.

Find the current directory and file's directory

To get the full path to the directory a Python file is contained in, write this in that file:

import os 
dir_path = os.path.dirname(os.path.realpath(__file__))

(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)

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To get the current working directory use

import os
cwd = os.getcwd()

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Documentation references for the modules, constants and functions used above:

• The os and os.path modules.
• The __file__ constant
• os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
• os.path.dirname(path) (returns "the directory name of pathname path")
• os.getcwd() (returns "a string representing the current working directory")
• os.chdir(path) ("change the current working directory to path")

How can I find script's directory?

You need to call os.path.realpath on __file__, so that when __file__ is a filename without the path you still get the dir path:

import os
print(os.path.dirname(os.path.realpath(__file__)))

How to get the name of the top most (entry) script in python?

Having switch my Google query to "how to to find the process name from python" vs how to find the "top level script name", I found this overly thorough treatment of the topic. The summary of which is the following:

import __main__
import os

appName = os.path.basename(__main__.__file__).strip(".py")

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