Counting the Number of Duplicates in a List

Python: count repeated elements in the list

You can do that using count:

my_dict = {i:MyList.count(i) for i in MyList}

>>> print my_dict     #or print(my_dict) in python-3.x
{'a': 3, 'c': 3, 'b': 1}

Or using collections.Counter:

from collections import Counter

a = dict(Counter(MyList))

>>> print a           #or print(a) in python-3.x
{'a': 3, 'c': 3, 'b': 1}

Trying to get a count of duplicate elements

If the Count is greater than one, check if a is not in the dup list, then add a to it.
Finally, print the length of the dup list

n=int(input("Enter the number of products to be stored in a list : "))

list1=[]

for i in range(n):
    item = int(input("value for product " + str(i+1) + " : "))
    list1.append(item)
    
dup = []

for a in list1:
    if (list1.count(a) > 1) and (a not in dup):
        dup.append(a)

print("Count of duplicate elements in the list: ", len(dup))

How do you find most duplicates in a 2d list?

One line splitted here:

[ a[k] 
  for k in range(len(a)) 
  if  a.count( a[k] ) > 1
  and k == a.index( a[k] ) ]

Count of duplicate items in a C# list

If you just need the total count:

var total = colorList.GroupBy(_ => _).Where(_ => _.Count() > 1).Sum(_ => _.Count());

An alternative which might be faster with large data sets:

var hashset = new HashSet<string>(); // to determine if we already have seen this color
var duplicates = new HashSet<string>(); // will contain the colors that are duplicates
var count = 0;
foreach (var color in colorList)
{
    if (!hashset.Add(color))
    {
        count++;
        if (duplicates.Add(color))
            count++;
    }
}

UPDATE: measured both methods with a list of 2^25 (approx. 30 million) entries: first one 3.7 seconds, second one 3.2 seconds.

How to count duplicate value in an array in javascript

function count() {    array_elements = ["a", "b", "c", "d", "e", "a", "b", "c", "f", "g", "h", "h", "h", "e", "a"];
    array_elements.sort();
    var current = null;    var cnt = 0;    for (var i = 0; i < array_elements.length; i++) {        if (array_elements[i] != current) {            if (cnt > 0) {                document.write(current + ' comes --> ' + cnt + ' times<br>');            }            current = array_elements[i];            cnt = 1;        } else {            cnt++;        }    }    if (cnt > 0) {        document.write(current + ' comes --> ' + cnt + ' times');    }
}
count();

List<String> list = new ArrayList<String>();
    list.add("a");
    list.add("b");
    list.add("c");
    list.add("a");
    list.add("a");
    list.add("a");

int countA=Collections.frequency(list, "a");
int countB=Collections.frequency(list, "b");
int countC=Collections.frequency(list, "c");