PHP: Count a stdClass object
The problem is that count is intended to count the indexes in an array, not the properties on an object, (unless it's a custom object that implements the Countable interface). Try casting the object, like below, as an array and seeing if that helps.
$total = count((array)$obj);
Simply casting an object as an array won't always work but being a simple stdClass object it should get the job done here.
count of stdClass objects Array in php
I have solved my question by following way:
foreach ($offers as $key=> $value)
{
echo "<br/>count->".count($value);
}
this loops itreate only once, and give me result.
Count Objects in PHP
From your example, using objects for this seems a very bloated method. Using a simple array would be much easier and faster.
This:
object(stdClass)#46 (3) {
["0"]=>
object(stdClass)#47 (1) {
["productid"]=>
string(2) "15"
}
}
Could just be this:
array(0 => 15);
Or even this:
array(15);
Your example only seems to be storing a product id, so you don't strictly need a key of "productid"
Is there any specific reason you need to use objects?
PHP: Count number of objects within another object?
count($hanap->data[0]->sections)
PHP: Count a stdClass object
The problem is that count is intended to count the indexes in an array, not the properties on an object, (unless it's a custom object that implements the Countable interface). Try casting the object, like below, as an array and seeing if that helps.
$total = count((array)$obj);
Simply casting an object as an array won't always work but being a simple stdClass object it should get the job done here.
Why does `count(new stdClass);` return 1?
If you read the documentation of the count function, you'll find this section about the return value:
Return Values
Returns the number of elements in array_or_countable. If the parameter
is not an array or not an object with implemented Countable interface,
1 will be returned. There is one exception, if array_or_countable is
NULL, 0 will be returned.
Get data from stdclass Object - Count from mysql
You have made life a little difficult for yourself by not giving the result column a nice easily accessible name
If you change your query so the column has a known name like this
$park = $wpdb->get_row("SELECT COUNT(1) as count
FROM wp_richreviews
WHERE review_status='1'");
then you have a nice easily accessible property called count
echo $park->count;
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