Notice: Trying to Get Property of Non-Object Error

What triggers the Trying to get property of non-object error

When you do find($id) and the record is not present, it returns null. So if you try to access any property ->column, it will throw error.

You can either do findOrFail($id) or have condition if (is_null($data)) or on frontend have $data->column ?? 'defaultvalue
'

Now, the second situation where your model is present but you still get error, do :

$data = Table::find($id);
dd(array_keys($data->toArray()));

You should see the column you are trying to access if it is present.

Lastly, if it is not present in above step but is there in the table, then check for protected $hidden = [] setting of your model which essentially hides certain columns.

php notice (trying to get property of non-object) error

Your function get_userdata() will return False on failure, WP_User object on success.

And error Trying to get property of non-object means that this function has returned false.

Simply check if $userInfo is not empty

$userInfo = get_userdata($userId);

if (!empty($userInfo)) {
    $usersNames[] = $userInfo->display_name;
}

Severity: Notice Trying to get property of non-object and did not get any data from database table codeigniter

I did not get product_id.I forgot to name the 'product_id' in my view page.When i placed the name='product_id' in view page, this actually solved the problem.

Fix error trying to get property of non-object Laravel

You're getting multiple records if you use get() method.

using first() you'll get only one collection.

Remove get(), and use only first() method

$name = '';
$sub = DB::table('hours')->join('projects', function($join) use ($projectID,$id){
                                $join->on('hours.project_id', '=', 'projects.id')
                                ->where('hours.project_id', '=', $projectID)
                                ->where('hours.id', '=', $id);
                            })->select('nameP')->first();
if(!empty($sub)){
    $name=$sub->nameP;
}

ERROR: Trying to get property id error in Laravel (non object)

I got it. the $categories variable the you pass to the view is an array, with keys are category ids and values are category names. In your view, inside the loop, that $category variable is a string, but you try to access that as an object ($category->id) and get the error.

SOLUTION 1:

You can update your code like this:

<select class="form-control" name="category_id" class="form-control @error('category_id') is-invalid @enderror" required>
@foreach($categories as $categoryId => $categoryName)
    <option value="{{ $categoryId }}" @isset($post) {{ $post->category->id == $categoryId ? 'selected' : '' }} @endisset>{{$categoryName}}</option>
@endforeach

<select class="form-control select2-multi" id="tags" name="tags[]" multiple>
    @foreach($tags as $tagId => $tagName)
        <option value="{{ $tagId }}" {{ old('tags[]', $post->tags)->contains($tagId) ? 'selected' : '' }}>{{ $tagName }}</option>
    @endforeach
</select>

SOLUTION 2:

I see that in the controller action, you transform you categories and tags to arrays, which is not necessary. Just get those from the database and pass to the view.

public function edit($id)
{
    // find the post in the database and save as a var
    $post = Post::find($id);

    $categories = Category::with('posts')->get();


    $tags = Tag::with('posts')->get();

    return view('backend.pages.posts.edit', [
        'post' => $post,
        'categories' => $categories,
        'tags' => $tags,
    ]);
    // Or you can even write: return view('backend.pages.posts.edit', compact('post', 'categories', 'tags'));
}

Then in your view:

<select class="form-control" name="category_id" class="form-control @error('category_id') is-invalid @enderror" required>
@foreach($categories as $category)
    <option value="{{ $category->id }}" @isset($post) {{ $post->category->id == $category->id ? 'selected' : '' }} @endisset>{{$category->name}}</option>
@endforeach

<select class="form-control select2-multi" id="tags" name="tags[]" multiple>
    @foreach($tags as $tag)
        <option value="{{ $tag->id }}" {{ old('tags[]', $post->tags)->contains($tag->id) ? 'selected' : '' }}>{{ $tag->name }}</option>
    @endforeach
</select>

Trying to get property 'id' of non-object only in my website

First of all, clear the caches with $promotion->id as using the below command.

php artisan config:cache
php artisan view:clear
php artisan route:clear

If you still get the error then use $promotion->userId as I have seen in your error the object contains userId, not an id.

Getting error- Trying to get property of non-object

$tenants is an object, with the property tenants. So, let's iterate it:

foreach($tenants->tenants as $row) {
?>
    <tr>
        <td data-field='name'><?php echo $row->name; ?></td>
         ...

Trying to get property of non-object - Laravel 5.6

The problem is that $surveys is coming back null so you must check it before accessing some property:

public function home(Request $request) 
{
    $respondent = null;
    $answers = null;
    $yet_to_respond = null;
    $no_response = null;

    $surveys = Survey::where('user_id', Auth::user()->id)->orderBy('created_at','DESC')->first();
    if($surveys){
        $respondent = Invite::where('user_id', Auth::user()->id)->where('survey_id', $surveys->id)->count();
        $answers = Invite::where('user_id', Auth::user()->id)->where('link_answered', 1)->where('survey_id', $surveys->id)->count();
        $yet_to_respond = Invite::where('user_id', Auth::user()->id)->where('link_clicked', 1)->where('survey_id', $surveys->id)->count();
        $no_response = Invite::where('user_id', Auth::user()->id)->where('link_clicked', 0)->where('survey_id', $surveys->id)->count();     
    }

    return view('home', compact('surveys','respondent','yet_to_respond','no_response','answers'));
}

Another way is to use optional() method and instead using $surveys->id you would be using optional($surveys)->id

The optional function accepts any argument and allows you to access properties or call methods on that object. If the given object is null, properties and methods will return null instead of causing an error:

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