Difference between two timestamp variable in php
Try this:
<?php
$end_date = "2014-10-09 15:03:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$diff = strtotime($now) - strtotime($end_date);
$fullDays = floor($diff/(60*60*24));
$fullHours = floor(($diff-($fullDays*60*60*24))/(60*60));
$fullMinutes = floor(($diff-($fullDays*60*60*24)-($fullHours*60*60))/60);
echo "Difference is $fullDays days, $fullHours hours and $fullMinutes minutes.";
Output:
Difference is -30 days, 0 hours and 39 minutes.
Demo:
http://3v4l.org/3auqe
Edit (using DATE OBJECT):
<?php
// Example 1
$end_date = "2014-09-11 20:35:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$date1=date_create($now);
$date2=date_create($end_date);
$diff=date_diff($date1,$date2,FALSE);
echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL;
//Output:
+2 days, 3 hours, 0 minutes, 44 seconds
// Example 2
$end_date = "2014-09-08 20:35:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$date1=date_create($now);
$date2=date_create($end_date);
$diff=date_diff($date1,$date2,FALSE);
echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL;
//Output:
-0 days, 20 hours, 0 minutes, 16 seconds
Demo:
http://3v4l.org/dPSgX#vhhvm-320
Diff between 2 timestamp - PHP
diff
is going to return a DateInterval object full of good information about the difference between your two dates. You're just trying to echo that object which won't work. Do a var_dump()
to see the object's properties:
$time = "2016-09-15 20:10:35";
$timenow = "2016-09-15 20:40:42";
$time = new DateTime($time);
$timenow = new DateTime($timenow);
$interval = $timenow->diff($time);
var_dump($interval);
Then you can echo out the properties like:echo $interval->i; // minutes
// 30
http://php.net/manual/en/class.dateinterval.php Difference between timestamps in minutes in PHP
Try using unix timestamp. Practically it measures the time in seconds from 1/1/1970 and it's a lot easier to use and understand than a php object.
$currentTimestamp = new DateTime()->getTimestamp();
$userLastActivity = date($date)->getTimestamp();
$timeLapse = (($currentDate - $userLastActivity)/60);
You should have the time saved as timestamp on the server too, in that case you could use the $date directly as a number, with no need for a conversion. And also, because it's universal, you can pass it around to javascript or any other language without any worries for conversion How do I find the hour difference between two dates in PHP?
You can convert them to timestamps and go from there:
$hourdiff = round((strtotime($time1) - strtotime($time2))/3600, 1);
Dividing by 3600 because there are 3600 seconds in one hour and using round()
to avoid having a lot of decimal places. How to get time difference in minutes in PHP
Subtract the past most one from the future most one and divide by 60.
Times are done in Unix format so they're just a big number showing the number of seconds from January 1, 1970, 00:00:00 GMT
Calculate difference between 2 times in hours in PHP
Convert them both to timestamp values, and then subtract to get the difference in seconds.
$ts1 = strtotime(str_replace('/', '-', '02/01/2013 08:24'));
$ts2 = strtotime(str_replace('/', '-', '31/12/2012 13:46'));
$diff = abs($ts1 - $ts2) / 3600;
How to calculate the difference between two dates using PHP?
You can use strtotime() to convert two dates to unix time and then calculate the number of seconds between them. From this it's rather easy to calculate different time periods.Use this for legacy code (PHP < 5.3). For up to date solution see jurka's answer below
$date1 = "2007-03-24";
$date2 = "2009-06-26";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
printf("%d years, %d months, %d days\n", $years, $months, $days);
Edit: Obviously the preferred way of doing this is like described by jurka below. My code is generally only recommended if you don't have PHP 5.3 or better. Several people in the comments have pointed out that the code above is only an approximation. I still believe that for most purposes that's fine, since the usage of a range is more to provide a sense of how much time has passed or remains rather than to provide precision - if you want to do that, just output the date.
Despite all that, I've decided to address the complaints. If you truly need an exact range but haven't got access to PHP 5.3, use the code below (it should work in PHP 4 as well). This is a direct port of the code that PHP uses internally to calculate ranges, with the exception that it doesn't take daylight savings time into account. That means that it's off by an hour at most, but except for that it should be correct.
<?php
/**
* Calculate differences between two dates with precise semantics. Based on PHPs DateTime::diff()
* implementation by Derick Rethans. Ported to PHP by Emil H, 2011-05-02. No rights reserved.
*
* See here for original code:
* http://svn.php.net/viewvc/php/php-src/trunk/ext/date/lib/tm2unixtime.c?revision=302890&view=markup
* http://svn.php.net/viewvc/php/php-src/trunk/ext/date/lib/interval.c?revision=298973&view=markup
*/
function _date_range_limit($start, $end, $adj, $a, $b, $result)
{
if ($result[$a] < $start) {
$result[$b] -= intval(($start - $result[$a] - 1) / $adj) + 1;
$result[$a] += $adj * intval(($start - $result[$a] - 1) / $adj + 1);
}
if ($result[$a] >= $end) {
$result[$b] += intval($result[$a] / $adj);
$result[$a] -= $adj * intval($result[$a] / $adj);
}
return $result;
}
function _date_range_limit_days($base, $result)
{
$days_in_month_leap = array(31, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
$days_in_month = array(31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
_date_range_limit(1, 13, 12, "m", "y", &$base);
$year = $base["y"];
$month = $base["m"];
if (!$result["invert"]) {
while ($result["d"] < 0) {
$month--;
if ($month < 1) {
$month += 12;
$year--;
}
$leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);
$days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];
$result["d"] += $days;
$result["m"]--;
}
} else {
while ($result["d"] < 0) {
$leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);
$days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];
$result["d"] += $days;
$result["m"]--;
$month++;
if ($month > 12) {
$month -= 12;
$year++;
}
}
}
return $result;
}
function _date_normalize($base, $result)
{
$result = _date_range_limit(0, 60, 60, "s", "i", $result);
$result = _date_range_limit(0, 60, 60, "i", "h", $result);
$result = _date_range_limit(0, 24, 24, "h", "d", $result);
$result = _date_range_limit(0, 12, 12, "m", "y", $result);
$result = _date_range_limit_days(&$base, &$result);
$result = _date_range_limit(0, 12, 12, "m", "y", $result);
return $result;
}
/**
* Accepts two unix timestamps.
*/
function _date_diff($one, $two)
{
$invert = false;
if ($one > $two) {
list($one, $two) = array($two, $one);
$invert = true;
}
$key = array("y", "m", "d", "h", "i", "s");
$a = array_combine($key, array_map("intval", explode(" ", date("Y m d H i s", $one))));
$b = array_combine($key, array_map("intval", explode(" ", date("Y m d H i s", $two))));
$result = array();
$result["y"] = $b["y"] - $a["y"];
$result["m"] = $b["m"] - $a["m"];
$result["d"] = $b["d"] - $a["d"];
$result["h"] = $b["h"] - $a["h"];
$result["i"] = $b["i"] - $a["i"];
$result["s"] = $b["s"] - $a["s"];
$result["invert"] = $invert ? 1 : 0;
$result["days"] = intval(abs(($one - $two)/86400));
if ($invert) {
_date_normalize(&$a, &$result);
} else {
_date_normalize(&$b, &$result);
}
return $result;
}
$date = "1986-11-10 19:37:22";
print_r(_date_diff(strtotime($date), time()));
print_r(_date_diff(time(), strtotime($date)));
Difference between 2 dates in seconds
$timeFirst = strtotime('2011-05-12 18:20:20');
$timeSecond = strtotime('2011-05-13 18:20:20');
$differenceInSeconds = $timeSecond - $timeFirst;
You will then be able to use the seconds to find minutes, hours, days, etc.
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