Rename File Command in Unix with Timestamp

Linux Rename file with only time/date stamp

mv myfile.txt `date +%Y_%m_%d_%H:%M:%S`.txt

Bash: Rename file name to unix timestamp of modification date

find . -type f -exec \
sh -c '
for i do
    d=$(dirname "$i")
    [ "$d" = / ] && d=
    n=${i##*/}
    echo mv "$i" "$d/u-$(stat -c %Y "$i") $n"
done' _ {} +

This operates recursively in the current directory (.). It only targets regular files (not directories etc). Modify -type f and other flags if needed.
It just prints the mv commands, so you can review them. Remove the echo to run for real.
We use find to list the target files, and its -exec flag to pass this list to a shell loop where we can parse and modify the filenames, including stat to get the modification time.
I don't know your use case, but a better solution may be to just save the output of: find . -type f -printf '%p u-%T@\n' in a file, for later reference (this prints the file path and modification time on the same line). Also, maybe a snapshot (if possible).

Renaming files in unix of particular date

You can modify a.sh like this :

find . -maxdepth 1 -type f -iname "*.temp" -exec bash -c 'mv $0 ${0//.temp/}' {} \;

newermt is for the date the file is modified last time.

and can execute it as

./a.sh 2017-09-27

To test if this command works on command line, you can try this outside your script:

find . -maxdepth 1 -type f -iname "*.temp" -exec bash -c 'mv $0 ${0//.temp/}' {} \;

linux-shell: renaming files to creation time

Naming based on file system date

In the linux shell:

for f in *.jpg
do
    mv -n "$f" "$(date -r "$f" +"%Y%m%d_%H%M%S").jpg"
done

Explanation:

for f in *.jpg do
This starts the loop over all jpeg files. A feature of this is that it will work with all file names, even ones with spaces, tabs or other difficult characters in the names.
mv -n "$f" "$(date -r "$f" +"%Y%m%d_%H%M%S").jpg"
This renames the file. It uses the -r option which tells date to display the date of the file rather than the current date. The specification +"%Y%m%d_%H%M%S" tells date to format it as you specified.
The file name, $f, is placed in double quotes where ever it is used. This assures that odd file names will not cause errors.
The -n option to mv tells move never to overwrite an existing file.
done
This completes the loop.

For interactive use, you may prefer that the command is all on one line. In that case, use:

for f in *.jpg; do mv -n "$f" "$(date -r "$f" +"%Y%m%d_%H%M%S").jpg"; done

Naming based on EXIF Create Date

To name the file based on the EXIF Create Date (instead of the file system date), we need exiftool or equivalent:

for f in *.jpg
do
    mv -n "$f" "$(exiftool -d "%Y%m%d_%H%M%S" -CreateDate "$f" | awk '{print $4".jpg"}')"
done

Explanation:

The above is quite similar to the commands for the file date but with the use of exiftool and awk to extract the EXIF image Create Date.

The exiftool command provides the date in a format like:
```
$ exiftool -d "%Y%m%d_%H%M%S"  -CreateDate sample.jpg
Create Date                     : 20121027_181338
```
The actual date that we want is the fourth field in the output.
We pass the exiftool output to awk so that it can extract the field that we want:
```
awk '{print $4".jpg"}'
```
This selects the date field and also adds on the .jpg extension.

how to rename an existing file with today's date

This is because a file name cannot contain slashes /. When you indicate

mv foo.c foo`date +%D`.c

It internally does:

mv foo.c foo01/10/14.c

so it tries to move the file foo.c into foo01/10 directory.

Instead, you can do:

date "+%F"

Which returns the date in a 2014-01-10 format and will expand into

mv foo.c foo2014-01-10.c