How to Check If a File Contains Only Zeros in a Linux Shell

How to check if a file contains only zeros in a Linux shell?

If you're using bash, you can use read -n 1 to exit early if a non-NUL character has been found:

<your_file tr -d '\0' | read -n 1 || echo "All zeroes."

where you substitute the actual filename for your_file.

How to check if a file is empty in Bash?

Misspellings are irritating, aren't they? Check your spelling of empty, but then also try this:

#!/bin/bash -e

if [ -s diff.txt ]; then
        # The file is not-empty.
        rm -f empty.txt
        touch full.txt
else
        # The file is empty.
        rm -f full.txt
        touch empty.txt
fi

I like shell scripting a lot, but one disadvantage of it is that the shell cannot help you when you misspell, whereas a compiler like your C++ compiler can help you.

Notice incidentally that I have swapped the roles of empty.txt and full.txt, as @Matthias suggests.

Find all zero-byte files in directory and subdirectories

To print the names of all files in and below $dir of size 0:

find "$dir" -size 0

Note that not all implementations of find will produce output by default, so you may need to do:

find "$dir" -size 0 -print

Two comments on the final loop in the question:

Rather than iterating over every other word in a string and seeing if the alternate values are zero, you can partially eliminate the issue you're having with whitespace by iterating over lines. eg:

printf '1 f1\n0 f 2\n10 f3\n' | while read size path; do
    test "$size" -eq 0 && echo "$path"; done

Note that this will fail in your case if any of the paths output by ls contain newlines, and this reinforces 2 points: don't parse ls, and have a sane naming policy that doesn't allow whitespace in paths.

Secondly, to output the data from the loop, there is no need to store the output in a variable just to echo it. If you simply let the loop write its output to stdout, you accomplish the same thing but avoid storing it.

How to check if a file contains a specific string using Bash

if grep -q SomeString "$File"; then
  Some Actions # SomeString was found
fi

You don't need [[ ]] here. Just run the command directly. Add -q option when you don't need the string displayed when it was found.

The grep command returns 0 or 1 in the exit code depending on
the result of search. 0 if something was found; 1 otherwise.

$ echo hello | grep hi ; echo $?
1
$ echo hello | grep he ; echo $?
hello
0
$ echo hello | grep -q he ; echo $?
0

You can specify commands as an condition of if. If the command returns 0 in its exitcode that means that the condition is true; otherwise false.

$ if /bin/true; then echo that is true; fi
that is true
$ if /bin/false; then echo that is true; fi
$

As you can see you run here the programs directly. No additional [] or [[]].

Unix to verify file has no content and empty lines

Your file might have new line character only.

Try this check:

[[ $(tr -d "\r\n" < file|wc -c) -eq 0 ]] && echo "File has no content"

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