glibc detected free(): invalid next size (fast)
bins =(double*)malloc(nbins * sizeof(double));
bin_counts =(int*)malloc((nbins-1) * sizeof(int));
//create bins from intervals
for(j=0; j<=(nbins); j++)
{
bins[j] = m + (j*interval);
}
//generate "bin_counts[]" with all 0's
for(y=0; y<=(nbins-1); y++)
{
bin_counts[y] = 0;
}
You are overstepping your arrays, you allocate place for nbins
doubles but write to nbins+1
locations, and use nbins
locations for bin_counts
but have only allocated nbins-1
.
Facing an error *** glibc detected *** free(): invalid next size (fast)
It could be that Java itself is linked against a different glibc than your libraries or that the libraries are linked differently/to different glibcs.
Also check if one of the libraries is linking against a debug version of the glibc (hat that problem on windows with the C++ runtime lib).
Try linking your libraries staticly against the glibc, or for the sake of excluding possibilities linking your wrapper and business libs staticly into one library.
*** glibc detected *** ./m: free(): invalid next size (fast) on trying to free heap memory
To expand on Daniel correctly pointing out that pt[end]
is incorrect, assume the following function call:
int values[] = { 0, 1, 2, 3, 4, 5, 6, 7 };
merge(values, 4, 5, 6);
In merge
, pt is allocated to be large enough for (6 - 4) + 1 = 3 int
s.tmp1
is set to 4.
On line 48, you do pt[tmp1] = arr[k]
, but this is pt[4] = arr[0]
, and you're writing on memory outside of pt
!
free char*: invalid next size (fast)
Your code is wrong.
You are allocating space for a single pointer (malloc(sizeof(char*))
), but no characters. You are overwriting your allocated space with all the strings, causing undefined behavior (in tihs particular case, corrupting malloc()
's book-keeping data).
You don't need to allocate space for the pointer (res
), it's a local variable. You must allocate space for all the characters you wish to store at the address held by the pointer.
Since you're going to be traversing a list to find strings to concatenate, you can't know the total size upfront. You're going to have to do two passes over the list: one to sum the strlen()
of each string
, then allocate that plus space for the separator and terminator, then another pass when you actually do the concatenenation.
*** glibc detected *** python: free(): invalid next size (fast):
You have corrupted the memory arena, plain and simple, possibly by writing beyond the end of the memory that was passed to the C function but, without seeing the source code, we'll never know for sure.
That message only appears when glib
detects that the memory allocation accounting information has been corrupted.
*** glibc detected *** : free(): invalid next size (fast) in C code
This bit of code is likely contributing to the problem (beginning at line 62):
for (i =0 ; i < order ; i++) { /*Stores the leaf key pointer pairs and new key pointer pairs in order form in temp. storage*/
if (i == InsertionIndex) {
i =i+1;
}
temp_keys[i] = bplus_IndividualKeyBplus(bplusLeaf,j);
temp_pointers[i] = bplus_IndividualPointersBplus(bplusLeaf,j);
j = j+1;
}
If InsertionIndex
is order-1
, a pair of out-of-buffer writes occur. Whatever immediately follows temp_key
and temp_pointers
is stomped upon, undoubted part of the heap used to manage other heap objects.
The construction itself is suspicious. Review the intent of the code and fix.
Error:free(): invalid next size (fast)
You are probably getting this due to writing outside the boundaries if the dataPage->data
entry. This struct entry is just a single byte long, so unless slot.slotaddress==0
and recordSize==1
, you will be writing to whatever memory lies after the end of the datapage
struct
. This memory corruption is probably what is causing your free
error.
To track down this type of error, I recommend running your program through valgrind
:
valgrind progname args
This in this case, you will probably get messages about "invalid writes", which tell you that you are writing outside the boundaries of your arrays.
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