Regular Expression for Ip Address Validation

Validating IPv4 addresses with regexp

You've already got a working answer but just in case you are curious what was wrong with your original approach, the answer is that you need parentheses around your alternation otherwise the (\.|$) is only required if the number is less than 200.

'\b((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)(\.|$)){4}\b'
^ ^

javascript regular expression to check for IP addresses

The regex you've got already has several problems:

Firstly, it contains dots. In regex, a dot means "match any character", where you need to match just an actual dot. For this, you need to escape it, so put a back-slash in front of the dots.

Secondly, but you're matching any three digits in each section. This means you'll match any number between 0 and 999, which obviously contains a lot of invalid IP address numbers.

This can be solved by making the number matching more complex; there are other answers on this site which explain how to do that, but frankly it's not worth the effort -- in my opinion, you'd be much better off splitting the string by the dots, and then just validating the four blocks as numeric integer ranges -- ie:

if(block >= 0 && block <= 255) {....}

Hope that helps.

How to validate an ip address with custom format using regular expression

Here's something you could try:

function customFormat(val) {  return /^(?=\d+\.\d+\.\d+\.\d+)(?:(?:25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.?){4} - ((?! -).)+ - \d{1,3}$/.test(val);}var testFormat = '213.39.59.78 - Public3 address.info - 24';document.getElementById('regex').innerHTML += testFormat + ' ' + (customFormat(testFormat) ? 'Valid Format!' : 'Invalid Format!');
<ul id="regex"></ul>

Regular expression to match DNS hostname or IP Address?

You can use the following regular expressions separately or by combining them in a joint OR expression.

ValidIpAddressRegex = "^(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$";

ValidHostnameRegex = "^(([a-zA-Z0-9]|[a-zA-Z0-9][a-zA-Z0-9\-]*[a-zA-Z0-9])\.)*([A-Za-z0-9]|[A-Za-z0-9][A-Za-z0-9\-]*[A-Za-z0-9])$";

ValidIpAddressRegex matches valid IP addresses and ValidHostnameRegex valid host names. Depending on the language you use \ could have to be escaped with \.


ValidHostnameRegex is valid as per RFC 1123. Originally, RFC 952 specified that hostname segments could not start with a digit.

http://en.wikipedia.org/wiki/Hostname

The original specification of
hostnames in RFC
952,
mandated that labels could not start
with a digit or with a hyphen, and
must not end with a hyphen. However, a
subsequent specification (RFC
1123)
permitted hostname labels to start
with digits.

Valid952HostnameRegex = "^(([a-zA-Z]|[a-zA-Z][a-zA-Z0-9\-]*[a-zA-Z0-9])\.)*([A-Za-z]|[A-Za-z][A-Za-z0-9\-]*[A-Za-z0-9])$";

Pattern validator is invalid for IP address regex

Since you are using Validators.pattern, you do not need to anchor the pattern manually (no need for word boundaries, angular will enclose the whole pattern with ^ and $ automatically) and you need to define it properly with a string literal doubling the escaping backslashes, else they will be removed by JS.

Use

const ipPattern = 
"(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)";

You may add ^ at the start and $ at the end just in case you want to keep the pattern explicit (it does not do any harm to have two ^ at the pattern start and $$ at the end, just the engine will check the start/end of the string positions twice).

NOTE: if you have more complex patterns with alternations, it is a good idea to use ^ and $ explicitly in those patterns since angular automatic anchoring does not enclose the whole pattern with an optional non-capturing group, it just appends ^ and $ to the provided pattern.

ip address validation in python using regex

Use anchors instead:

aa=re.match(r"^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$",ip)

These make sure that the start and end of the string are matched at the start and end of the regex. (well, technically, you don't need the starting ^ anchor because it's implicit in the .match() method).

Then, check if the regex did in fact match before trying to access its results:

if aa:
ip = aa.group()

Of course, this is not a good approach for validating IP addresses (check out gnibbler's answer for a proper method). However, regexes can be useful for detecting IP addresses in a larger string:

ip_candidates = re.findall(r"\b\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\b", ip)

Here, the \b word boundary anchors make sure that the digits don't exceed 3 for each segment.

Using a RegEx to match IP addresses

You have to modify your regex in the following way

pat = re.compile("^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$")

that's because . is a wildcard that stands for "every character"



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