Regexp to Match Every Occurence After N Occurences

let str = 'I amx nexver axt hoxme on Sxundxaxs';let n = 3;let ch = 'x';
let regex = new RegExp("((?:[^" +ch+ "]*" +ch+ "){" + (n-1) + "}[^" +ch+ "]*)" +ch, "g");
str = str.replace(regex, '$1y');
console.log(str);//=> I amx nexver ayt hoxme on Sxundyaxs

Match all after nth occurrence of specified character

I would propose this:

[^"]*(?=";)

This only matches the part within quotes, excluding (but requiring) the ending ";.

See demo on regex101

regular expression capture nth match

for nth match use this pattern (?:.*?\$[0-9.]+){XX}.*?(\$[0-9.]+)

where XX = n-1

Example for 3rd match

regular expression to match everything until the last occurrence of /

You can match this:

.*\/

and replace with your text.

DEMO

Javascript Regex match everything after last occurrence of string

One option would be to match everything up until the last [/quote], and then get anything following it. (example)

/.*\[\/quote\](.*)$/i

This works since .* is inherently greedy, and it will match every up until the last \[\/quote\].

Based on the string you provided, this would be the first capturing group match:

\nThis is all the text I\'m wirting about myself.\n\nLook at me ma. Javascript.

But since your string contains new lines, and . doesn't match newlines, you could use [\s\S] in place of . in order to match anything.

Updated Example

/[\s\S]*\[\/quote\]([\s\S]*)$/i

You could also avoid regex and use the .lastIndexOf() method along with .slice():

Updated Example

var match = '[\/quote]';
var textAfterLastQuote = str.slice(str.lastIndexOf(match) + match.length);
document.getElementById('res').innerHTML = "Results: " + textAfterLastQuote;

Alternatively, you could also use .split() and then get the last value in the array:

Updated Example

var textAfterLastQuote = str.split('[\/quote]').pop();
document.getElementById('res').innerHTML = "Results: " + textAfterLastQuote;

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