Merge Two Json/Javascript Arrays in to One Array

Merge two JSON objects containing arrays using jQuery

If you look at the documentation of jquery extend you can see that you can pass deep as first argument:

var obj = $.extend(true, {},json1,json2);

With your test data, because the keys in the objects are named the same, the result will just have the second set of objects.

If you want some other result you need to update your question to clarify the desired effect.

Update

If you want the entries to be combined you can do something like this:

var entries = json1.entry.concat(json2.entry);
console.log(entries);

Javascript: Merge List of JSON Objects on Same Key and Drop Un-merged Objects

You can use es6 spread (...) operator to marge two objects.

let arrObjA = [{ "index": 114, "realName": 'kevin', "bucket": 'boss', "react_name": 'BossKevin' }, { "index": 115, "realName": 'angela', "bucket": 'boss', "react_name": 'BossAngela' }, { "index": 116, "realName": 'james', "bucket": 'janitor', "react_name": 'JanitorJames' }, { "index": 117, "realName": 'arthur', "bucket": 'employee', "react_name": 'EmployeeArthur' }]
let arrObjB = [{ "boxName": "building", "realName": "angela", "boxValue": "2" }, { "boxName": "building", "realName": "james", "boxValue": "false" }, { "boxName": "building", "realName": "arthur", "boxValue": "0" },]

let result = arrObjB.map(item => ({
    ...arrObjA.find(({ realName }) => item.realName == realName),
    ...item,
}));

console.log(result)

How to merge multiple object arrays into one array cross with sub array?

You could iterate over the two arrays like this and push the merged values into result:

arr1.forEach(e => {
  arr2.forEach(e2 => {
    result.push(Object.assign({}, e, e2));
  });
});

Which could also be written in ONE LINE:

arr1.forEach(e => arr2.forEach(e2 => result.push(Object.assign({}, e, e2))));

const arr1 = [{    "userId": 9  },  {    "userId": 14  }];
const arr2 = [{  "role": "1",  "group": "3"}, {  "role": "1",  "group": "2"}];
const result = [];
arr1.forEach(e => {  arr2.forEach(e2 => {    result.push(Object.assign({}, e, e2));  });});
console.log(result);

How to join two JSON Array objects in Node

i already got an answer from the link provided by Pravin

var merge = function() {
var destination = {},
    sources = [].slice.call( arguments, 0 );
sources.forEach(function( source ) {
    var prop;
    for ( prop in source ) {
        if ( prop in destination && Array.isArray( destination[ prop ] ) ) {

            // Concat Arrays
            destination[ prop ] = destination[ prop ].concat( source[ prop ] );

        } else if ( prop in destination && typeof destination[ prop ] === "object" ) {

            // Merge Objects
            destination[ prop ] = merge( destination[ prop ], source[ prop ] );

        } else {

            // Set new values
            destination[ prop ] = source[ prop ];

        }
    }
});
return destination;
};

console.log(JSON.stringify(merge({ a: { b: 1, c: 2 } }, { a: { b: 3, d: 4 } })));

Merge two json array into one

There are some missing pieces there, but I think I see what's happening.

Based on the result you're getting, it looks like $posts and $post_image in this code are eloquent models.

return $this->successResponse($posts.$post_image );

When you concatenate them, their __toString() methods convert them to strings, which is done using the toJson() method. So basically you have two JSON objects stuck together, which isn't valid JSON, and then the successResponse() method encodes them again.

To merge them, you can convert them to arrays, merge those, then pass the result to successResponse().

$merged = array_merge($posts->toArray(), $post_image->toArray());
return $this->successResponse($merged);

The result you want is impossible, though. The "post" object has two different values of "id". You'll only be able to get one. If you use

$merged = array_merge($posts->toArray(), $post_image->toArray());

Then the id value of the second object will replace the first one. If you want to keep the first id value, you need to use union instead of array_merge.

$merged = $a->toArray() + $b->toArray();