How to Test Valid Uuid/Guid

How to test valid UUID/GUID?

Currently, UUID's are as specified in RFC4122. An often neglected edge case is the NIL UUID, noted here. The following regex takes this into account and will return a match for a NIL UUID. See below for a UUID which only accepts non-NIL UUIDs. Both of these solutions are for versions 1 to 5 (see the first character of the third block).

Therefore to validate a UUID...

/^[0-9a-f]{8}-[0-9a-f]{4}-[0-5][0-9a-f]{3}-[089ab][0-9a-f]{3}-[0-9a-f]{12}$/i

...ensures you have a canonically formatted UUID that is Version 1 through 5 and is the appropriate Variant as per RFC4122.

NOTE: Braces { and } are not canonical. They are an artifact of some systems and usages.

Easy to modify the above regex to meet the requirements of the original question.

HINT: regex group/captures

To avoid matching NIL UUID:

/^[0-9a-f]{8}-[0-9a-f]{4}-[1-5][0-9a-f]{3}-[89ab][0-9a-f]{3}-[0-9a-f]{12}$/i

How to check UUID validity in Python?

I found this question while I was looking for a Python answer. To help people in the same situation, I've added the Python solution.

You can use the uuid module:

#!/usr/bin/env python

from uuid import UUID

def is_valid_uuid(uuid_to_test, version=4):
    """
    Check if uuid_to_test is a valid UUID.
    
     Parameters
    ----------
    uuid_to_test : str
    version : {1, 2, 3, 4}
    
     Returns
    -------
    `True` if uuid_to_test is a valid UUID, otherwise `False`.
    
     Examples
    --------
    >>> is_valid_uuid('c9bf9e57-1685-4c89-bafb-ff5af830be8a')
    True
    >>> is_valid_uuid('c9bf9e58')
    False
    """
    
    try:
        uuid_obj = UUID(uuid_to_test, version=version)
    except ValueError:
        return False
    return str(uuid_obj) == uuid_to_test

if __name__ == '__main__':
    import doctest
    doctest.testmod()

How to check the validity of a GUID (or UUID) using NSRegularExpression or any other effective way in Objective-C

This regex matches for me

\A\{[A-F0-9]{8}-[A-F0-9]{4}-[A-F0-9]{4}-[A-F0-9]{4}-[A-F0-9]{12}\}\Z

In short:

• \A and \Z is the beginning and end of the string
• \{ and \} is escaped curly bracets
• [A-F0-9]{8} is exactly 8 characters of either 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F

As an NSRegularExpression it would look like this

NSError *error = NULL;
NSRegularExpression *regex = 
  [NSRegularExpression regularExpressionWithPattern:@"\\A\\{[A-F0-9]{8}-[A-F0-9]{4}-[A-F0-9]{4}-[A-F0-9]{4}-[A-F0-9]{12}\\}\\Z" 
                                            options:NSRegularExpressionAnchorsMatchLines 
                                              error:&error];
// use the regex to match the string ...

How to validate UUID v4 in Go?

Try with...

func IsValidUUID(uuid string) bool {
    r := regexp.MustCompile("^[a-fA-F0-9]{8}-[a-fA-F0-9]{4}-4[a-fA-F0-9]{3}-[8|9|aA|bB][a-fA-F0-9]{3}-[a-fA-F0-9]{12}$")
    return r.MatchString(uuid)
}

Live example: https://play.golang.org/p/a4Z-Jn4EvG

Note: as others have said, validating UUIDs with regular expressions can be slow. Consider other options too if you need better performance.

How to check UUID validity in Python?

I found this question while I was looking for a Python answer. To help people in the same situation, I've added the Python solution.

You can use the uuid module:

#!/usr/bin/env python

from uuid import UUID

def is_valid_uuid(uuid_to_test, version=4):
    """
    Check if uuid_to_test is a valid UUID.
    
     Parameters
    ----------
    uuid_to_test : str
    version : {1, 2, 3, 4}
    
     Returns
    -------
    `True` if uuid_to_test is a valid UUID, otherwise `False`.
    
     Examples
    --------
    >>> is_valid_uuid('c9bf9e57-1685-4c89-bafb-ff5af830be8a')
    True
    >>> is_valid_uuid('c9bf9e58')
    False
    """
    
    try:
        uuid_obj = UUID(uuid_to_test, version=version)
    except ValueError:
        return False
    return str(uuid_obj) == uuid_to_test

if __name__ == '__main__':
    import doctest
    doctest.testmod()

PHP verify valid UUID

According to Wikipedia the format of UUID v4 is:

Version 4 UUIDs have the form xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx
where x is any hexadecimal digit and y is one of 8, 9, A, or B. e.g.
f47ac10b-58cc-4372-a567-0e02b2c3d479.

The corresponding regex is:

/^[0-9A-F]{8}-[0-9A-F]{4}-4[0-9A-F]{3}-[89AB][0-9A-F]{3}-[0-9A-F]{12}$/i

How to judge a string is UUID type?

You should use regex to verify it e.g.:

^[0-9a-fA-F]{8}-[0-9a-fA-F]{4}-[0-9a-fA-F]{4}-[0-9a-fA-F]{4}-[0-9a-fA-F]{12}$

test it with e.g.g 01234567-9ABC-DEF0-1234-56789ABCDEF0

or with brackets

^\{?[0-9a-fA-F]{8}-[0-9a-fA-F]{4}-[0-9a-fA-F]{4}-[0-9a-fA-F]{4}-[0-9a-fA-F]{12}‌​\}?$

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