How to Check If a Number Is Between Two Values

How to check if a number is between two values?

Tests whether windowsize is greater than 500 and lesser than 600 meaning that neither values 500 or 600 itself will result in the condition becoming true.

if (windowsize > 500 && windowsize < 600) {
  // ...
}

Check if a variable is between two numbers with Java

I see some errors in your code.

Your probably meant the mathematical term

90 <= angle <= 180, meaning angle in range 90-180.

if (angle >= 90 && angle <= 180) {

// do action
}

Determine whether integer is between two other integers

if 10000 <= number <= 30000:
    pass

For details, see the docs.

How to elegantly check if a number is within a range?

There are a lot of options:

int x = 30;
if (Enumerable.Range(1,100).Contains(x))  //true

And indeed basic if more elegantly can be written with reversing order in the first check:

if (1 <= x && x <= 100)   //true

Also, check out this SO post for regex options.

Notes:

LINQ solution is strictly for style points - since Contains iterates over all items its complexity is O(range_size) and not O(1) normally expected from a range check.

More generic version for other ranges (notice that second argument is count, not end):
```
if (Enumerable.Range(start, end - start + 1).Contains(x)
```
There is temptation to write if solution without && like 1 <= x <= 100 - that look really elegant, but in C# leads to a syntax error "Operator '<=' cannot be applied to operands of type 'bool' and 'int'"

Objective-C: How to check a number is between two values

Unless your compiler is broken there is nothing wrong with that code. There is probably something wrong with x

As Sascha stated in the comments make sure that x is not an NSNumber. The reason for this is if x is an NSNumber then the value stored in it is a pointer which value would likely be much higher than 100 (0x4FBC60 for example) and you would want to compare against the -(int)intValue.

Other things to consider are comparing against the right data. While implicit number conversions work well you may want to use the same literal comparison as your data type.

unsigned long long x = 51ull;
if(x > 50ull && x < 100ull)
{

}

how to see if there is a value in a list that is between two values from another list

It really depends on what you want it to return. I wrote a code that will return the first pattern that it finds, but with some changes I'm sure it would not be difficult to return all combinations.

def get_between(a, b):
    a, b = sorted(a), sorted(b)
    
    for b_value in b:
        smaller = None
        greater = None
        for a_value in a:
            if b_value > a_value:
                smaller = a_value
            elif b_value < a_value:
                greater = a_value
            
            if smaller and greater:
                return f"{b_value} is between {smaller} and {greater}"
    
    return "There is no such combination"

a = [1, 4, 12]
b = [2, 13]
print(get_between(a, b))

The output on that case will be 2 is between 1 and 4, but you can adapt the return value to be whatever you want.

python check two values to be between two values

This code should get you the required result

val1 = 23.04
val2 = 29.04

tobe1 = 24.04
tobe2 = 27.04

your_list = [tobe1, tobe2]
if all(val1 < x < val2 for x in (tobe1, tobe2)):
    print("something")

If you want ALL values in (tobe1, tobe2) to be within the val1 and val2, then use all

If you want ANY value in (tobe1, tobe2) to be within the val1 and val2, then use any.

How to Check If a Number Is Between Two Values