Springboot Data - No Property Registration Found

PropertyReferenceException No property id found for type UserRegistration

You don't have to declare separate query method for finding by ID, you can just add @Column annotation for you id property.

@Id
@Column("user_id") // or whatever it's called in the SQL table
@GeneratedValue(strategy = GenerationType.AUTO)
val userId:Long=-1

and then use standard method (Optional<T> findById(ID id);) inherited from JpaRepository

val userRegistration:UserRegistration? = 
           userRegistrationRepository.findById(userId).orElse(null)

No property found for type... custom Spring Data repository

The problem here is that you are creating FilterRepositoryImpl but you are using it in UserRepository. You need to create UserRepositoryImpl to make this work.

Read this doc for more detail

Basically

public interface UserRepositoryCustom {
    List<User> filterBy(String role);
}

public class UserRepositoryImpl implements UserRepositoryCustom {
...
}

public interface UserRepository extends JpaRepository<User, String>, UserRepositoryCustom {
...
}

Spring Data 2.x update

This answer was written for Spring 1.x. As Matt Forsythe pointed out, the naming expectations changed with Spring Data 2.0. The implementation changed from the-final-repository-interface-name-with-an-additional-Impl-suffix to the-custom-interface-name-with-an-additional-Impl-suffix.

So in this case, the name of the implementation would be: UserRepositoryCustomImpl.

No property date found for type cashflow in Springboot app

The stracktrace tells you what the problem is

at org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:293) ~[spring-data-commons-2.1.9.RELEASE.jar:2.1.9.RELEASE] at 
org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:276) ~[spring-data-commons-2.1.9.RELEASE.jar:2.1.9.RELEASE] at
 org.springframework.data.jpa.repository.query.QueryUtils.toJpaOrder(QueryUtils.java:565) ~[spring-data-jpa-2.1.9.RELEASE.jar:2.1.9.RELEASE] at
 org.springframework.data.jpa.repository.query.QueryUtils.toOrders(QueryUtils.java:518) ~[spring-data-jpa-2.1.9.RELEASE.jar:2.1.9.RELEASE] at 

This clearly states that when generating the ordering clause it breaks on an unknown property. The ordering is done based in the passed in Pageable which you construct in your controller. The construction depends on a passed in request parameter sortBy, which has a default value of date.

Now when the parameter isn't present this value is used, as your entity doesn't have a date property it will break.

Either remove the ordering or provide a valid default.

PropertyReferenceException:No property

The exception explains in some detail what is going wrong (I added line breaks to make it easier to read):

Failed to create query for method 
public abstract java.util.List com.self.learning.jwtAuthApp.repository.StateRepository.findAllByCountry_Code(java.lang.String)! 
No property code found for type Country! 
Traversed path: State.country.

What this tells you is that Spring Data tries to create the implementation for the method findAllByCountry_Code but can't find a matching property.
Specifically it found the property country which is of type Country and now fails to find a property code in the type Country.

If one compares that with your entity one has to agree.
There is no code in Country there is only a countryCode which you probably want to refer to.
So the correct method name should be

findAllByCountry_CountryCode

Alternatively you could rename the property Country.countryCode to Country.code which in my opinion would would be the better solution since the repeated country is really just noise and should be dropped in the first place.

Caused by: org.springframework.data.mapping.PropertyReferenceException: No property languageId found for type Project

If you want to filter on properties not on the aggregate root you'll have to provide the full path.
The following should work.

public List<Project> findProjectByProjectIdAndProjectDetailsLanguageId(int projectId , int languageId);

org.springframework.data.mapping.PropertyReferenceException: No property catch found for type

I had a issue like this and my mistake was the name of the custom repository class:

If the name of your jpa repository interface is LocaleJpaRepository, your new custom interface should be named LocaleJpaRepositoryCustom, but the class that makes the override in the method must be named LocaleJpaRepositoryImpl, as it follows:

public class LocalJpaRepositoryImpl implements LocalJpaRepositoryCustom{
@Override
   public void customMethod(){....}
}

Basically, the implementation class of your custom interface should start with the name of your repository interface (JPARepository) ending with 'Impl' keyword.

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