How to elegantly check if a number is within a range?
There are a lot of options:
int x = 30;
if (Enumerable.Range(1,100).Contains(x)) //true
And indeed basic if
more elegantly can be written with reversing order in the first check:
if (1 <= x && x <= 100) //true
Also, check out this SO post for regex options.
Notes:
LINQ solution is strictly for style points - since Contains iterates over all items its complexity is O(range_size) and not O(1) normally expected from a range check.
More generic version for other ranges (notice that second argument is count, not end):if (Enumerable.Range(start, end - start + 1).Contains(x)
There is temptation to write
if
solution without&&
like1 <= x <= 100
- that look really elegant, but in C# leads to a syntax error "Operator '<=' cannot be applied to operands of type 'bool' and 'int'"
How to check if an integer is within a range of numbers in PHP?
The expression:
($min <= $value) && ($value <= $max)
will be true if $value
is between $min
and $max
, inclusively
See the PHP docs for more on comparison operators
How to check if a number falls in a given range
This the simplest way:
$check = 0;
$nextCheck = $check+1001;
while ($check < 100001) {
If ($user_id > $check && $user_id < $nextCheck) {
// Code ...
break;
} else {
$check+=1000;
$nextCheck+=1000;
}
}
check if number is in given range?
Rather than looping, you can directly check whether:
if n>=r['min'] and n<=r['max']:
return True
else:
return False
Easily check if a number is in a given Range in Dart?
Quite simply, no. Just use 1 <= i && i <= 10
.
How to check if an integer is within a range?
Tested your 3 ways with a 1000000-times-loop.
t1_test1: ($val >= $min && $val <= $max)
: 0.3823 ms
t2_test2: (in_array($val, range($min, $max))
: 9.3301 ms
t3_test3: (max(min($var, $max), $min) == $val)
: 0.7272 ms
T1 was fastest, it was basicly this:
function t1($val, $min, $max) {
return ($val >= $min && $val <= $max);
}
Check if value is between a range of numbers
Use this:
final String checkage = age.getText().toString();
int value = Integer.parseInt(checkage);
if(value >= 4 && value <= 80) {
Toast.makeText(this, "You must be older than 4 and younger than 80", Toast.LENGTH_SHORT).show();
return;
}
'||' won't be useful for you in this case.
How to quickly check if an Integer lies within a given range
You can create a range and check if it contains x
:
let contains = (lowerBounds...upperBounds).contains(x)
e.g.:
let successful = (200..<300).contains(httpStatusCode)
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