Set<Nsobject>' Does Not Have a Member Named 'Anyobject." - Xcode 6.3

[NSObject : AnyObject]?' does not have a member named 'subscript' in Xcode 6 Beta 6

The error message is saying you can't do [] on Optional value. What you need to do is unwrap it.

error.userInfo!["error"] as NSString

or if you want to be safe

if let errorString = error.userInfo?["error"] as NSString {
     println(errorString)
}

[NSObject : AnyObject]?' does not have a member named 'subscript' error in Xcode 6 beta 6

As mentioned in the Xcode 6 beta 6 release notes, a large number of Foundation APIs have been audited for optional conformance.
These changes replace T! with either T? or T depending on whether the value can be null (or not) respectively.

notification.userInfo is now an optional dictionary:

class NSNotification : NSObject, NSCopying, NSCoding {
    // ...
    var userInfo: [NSObject : AnyObject]? { get }
    // ...
}

so you have to unwrap it. If you know that userInfo is not nil then
you can simply use a "forced unwrapping":

var info = notification.userInfo!

but note that this will crash at runtime if userInfo is nil.

Otherwise better use an optional assignment:

if let info = notification.userInfo {
    var keyboardFrame: CGRect = (info[UIKeyboardFrameEndUserInfoKey] as! NSValue).CGRectValue()
} else {
    // no userInfo dictionary present
}

Swift : '(NSObject, AnyObject)' does not have a member named 'subscript'

The shortest one is:

// Xcode 6.0.1
func handleRemoteNotifiation(userInfo: [NSObject : AnyObject]) {
    if let badge = [userInfo["aps"]?["badge"]][0] as? Int {
        self.updateAppIconBadgeNumber(badge)
    }
}

// Xcode 6.1
func handleRemoteNotifiation(userInfo: [NSObject : AnyObject]) {
    if let badge = userInfo["aps"]?["badge"] as? Int {
        self.updateAppIconBadgeNumber(badge)
    }
}

? between ["aps"] and ["badge"] is called "Optional Chaining".
You need this because userInfo["aps"] can returns nil.
And you don't have to cast it to [String : AnyObject] because every AnyObject has 'subscript' member.

And, Why we need [ ... ][0] in Xcode 6.0.1 is... I don't know :( .a bug, maybe.

event.touchesForView().AnyObject() not working in Xcode 6.3

In 1.2, touchesForView now returns a native Swift Set rather than an NSSet, and Set doesn't have an anyObject() method.

It does have a first method, which is much the same thing. Note, also, that you won't be able to use as? any more, you'll have to cast it using as? and handle the nil possibility, here's one approach:

func doSomethingOnDrag(sender: UIButton, event: UIEvent) {
    if let touch = event.touchesForView(sender)?.first as? UITouch,
           location = touch.locationInView(sender) {
            // use location
    }
}

AnyObject does not have a member named sort

Don't access the array as an "AnyObject". Try pulling it as an Array object.

var savedDataArray: Array<String>? = NSUserDefaults.standardUserDefaults().objectForKey("savedDataArray") as? Array<String>;

Substitute the "String" type for whatever you're pulling the objects in your Array as. This allows you to use the "sort" member.

(key: AnyObject, value: AnyObject)' does not have a member named 'subscript'

'(key: AnyObject, value: AnyObject)' indicates that item is not an Dictionary but is a Tuple with a single key/value pair.

Iterating dictionaries in swift interates through tuples:

for (key, value) in json {
    println(key, value)
}

Your for loop indicates that you are probably wanting a json Array of tuples instead of a json Dictionary.

item["id"] would give you a compile time error if you declared the parameter as a tuple. It seems you stumbled onto something hidden with the language with how either tuples or subscripts work under the hood.