How to call a method after a delay in Android
Kotlin
Handler(Looper.getMainLooper()).postDelayed({
//Do something after 100ms
}, 100)
Java
final Handler handler = new Handler(Looper.getMainLooper());
handler.postDelayed(new Runnable() {
@Override
public void run() {
//Do something after 100ms
}
}, 100);
How to run code after some delay in Flutter?
Figured it out /p>
class AnimatedFlutterLogo extends StatefulWidget {
@override
State<StatefulWidget> createState() => new _AnimatedFlutterLogoState();
}
class _AnimatedFlutterLogoState extends State<AnimatedFlutterLogo> {
Timer _timer;
FlutterLogoStyle _logoStyle = FlutterLogoStyle.markOnly;
_AnimatedFlutterLogoState() {
_timer = new Timer(const Duration(milliseconds: 400), () {
setState(() {
_logoStyle = FlutterLogoStyle.horizontal;
});
});
}
@override
void dispose() {
super.dispose();
_timer.cancel();
}
@override
Widget build(BuildContext context) {
return new FlutterLogo(
size: 200.0,
textColor: Palette.white,
style: _logoStyle,
);
}
}
Execute script after specific delay using JavaScript
There is the following:
setTimeout(function, milliseconds);
function which can be passed the time after which the function will be executed.
See: Window setTimeout()
Method.
How to call a function after delay in Kotlin?
You can use Schedule
inline fun Timer.schedule(
delay: Long,
crossinline action: TimerTask.() -> Unit
): TimerTask (source)
example (thanks @Nguyen Minh Binh - found it here: http://jamie.mccrindle.org/2013/02/exploring-kotlin-standard-library-part-3.html)
import java.util.Timer
import kotlin.concurrent.schedule
Timer("SettingUp", false).schedule(500) {
doSomething()
}
self-triggered always block using delay
I have chanaged your code and this new code works fine for me. If you think it is not working, maybe you are wrong in understanding Verilog simulation. Non-blocking delays schedule an event on a signal. If before the time of assigning that scheduling, another event is scheduled, with a different value, it overrides the first one. If new event has the same value, the first one is kept.
// Verilog
// self-triggered always block
// block should take time steps <= dtmax
`define tick 1.0e-9
module dut(eflag);
input eflag;
reg iflag;
reg toggle;
integer iticks;
real last_time;
real now;
real dtlast;
real dtmax;
always @(eflag, iflag) begin
now = $time*`tick;
dtlast = now - last_time;
dtmax = iticks*`tick; // from last call
$display( "dtlast: %g",dtlast);
$display( "err: %d",dtlast > dtmax); // giving wrong value in sim?
$display("\nnow: %g",now);
$display( "dtmax: %g",dtmax);
// time step control dummy
iticks <= 7 + $random % 5; //changed because in previous one eflag and toggle always changed at the same time
toggle = !toggle;
last_time = now;
end
initial toggle = 0;
initial iflag = 0;
always @(toggle) begin
#(iticks) iflag <= !iflag;
end
endmodule
How to create a delay in Swift?
Instead of a sleep, which will lock up your program if called from the UI thread, consider using NSTimer
or a dispatch timer.
But, if you really need a delay in the current thread:
do {
sleep(4)
}
This uses the sleep
function from UNIX.
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