Creating a Segue Programmatically

Creating a segue programmatically

By definition a segue can't really exist independently of a storyboard. It's even there in the name of the class: UIStoryboardSegue. You don't create segues programmatically - it is the storyboard runtime that creates them for you. You can normally call performSegueWithIdentifier: in your view controller's code, but this relies on having a segue already set up in the storyboard to reference.

What I think you are asking though is how you can create a method in your common view controller (base class) that will transition to a new view controller, and will be inherited by all derived classes. You could do this by creating a method like this one to your base class view controller:

- (IBAction)pushMyNewViewController
MyNewViewController *myNewVC = [[MyNewViewController alloc] init];

// do any setup you need for myNewVC

[self presentModalViewController:myNewVC animated:YES];

and then in your derived class, call that method when the appropriate button is clicked or table row is selected or whatever.

Creating a segue programmatically without a storyboard

I assume you meant a ViewController by the word page. So initialize your ViewController inside your func regSegue(){...} and present it using present(_:animated:completion:) method.


func regSegue(){
let page = PageViewController()
present(page, animated: true, completion: nil)

Perform a segue programmatically

Segues are components of storyboard. If you don't have a storyboard, you can't perform segues. But you can use present view controller like this:

let vc = ViewController() //your view controller
self.present(vc, animated: true, completion: nil)

How to add a segue programmatically?

Make sure your tableview delegate is set. If you are using storyboard, make sure delegate outlet in your storyboard is connected properly. If you are creating tableview by code, then you should do tableView.delegate=self; to set the delegate.

Your code is fine.

And one more thing:

You might need to change this line:

     performSegueWithIdentifier("showContent", sender: tableView)

you need to make the sender as the row but not the tableview,so that the prepare for segue will get the sender as row instead of whole tableview.

As you are calling the prepareForSegue overtime you select a row, it makes sense to make the row as sender in performSegueWithIdentifier.

So it would be:

            let row=indexPAth.row
performSegueWithIdentifier("showContent", sender: row)

Make Segue programmatically in Swift

You can do it like proposed in this answer:

Furthermore I am providing you the code from the linked answer rewritten in Swift because the answer in the link was originally written in Objective-C.

let vc = UIStoryboard(name:"Main", bundle:nil).instantiateViewController(withIdentifier: "identifier") as! SecondViewController

vc.resultsArray = self.resultsArray


Since this answer draws some attention I thought I provide you with another more failsafe way. In the above answer the application will crash if the ViewController with "identifier" is not of type SecondViewController. In Swift you can prevent this crash by using optional binding:

guard let vc = UIStoryboard(name:"Main", bundle:nil).instantiateViewControllerWithIdentifier("identifier") as? SecondViewController else {
print("Could not instantiate view controller with identifier of type SecondViewController")

vc.resultsArray = self.resultsArray
self.navigationController?.pushViewController(vc, animated:true)

This way the ViewController is pushed if it is of type SecondViewController. If can not be casted to SecondViewController a message is printed and the application remains on the current ViewController.

Segue and Button programmatically swift

Create seuge

Create Seuge

Assign identifier

Sample Image

and your button target

 @IBAction func button_clicked(_ sender: UIButton) {
self.performSegue(withIdentifier: "segueToNext", sender: self)

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "segueToNext" {
if let destination = segue.destination as? Modo1ViewController {
destination.nomb = nombres // you can pass value to destination view controller

// destination.nomb = arrayNombers[(sender as! UIButton).tag] // Using button Tag

How can I create a segue programmatically to pass info between view controllers - Swift

Since you says "Those view controllers are created in the storyboard" I believe that you can use performSegueWithIdentifier and prepareForSegue:

Declare your variable outside your okButton method.

    let targetValue = 10 // this is just to test the first case
let currentValue = 10 // this is just to test the first case
var score = 0
var point = 0

@IBAction func okButton(sender: AnyObject) {

let diferencia = abs(targetValue - currentValue)
point = 100 - diferencia
score += point
func bonusPoints(){
score += 100

if diferencia == 0{
performSegueWithIdentifier("GonPerfectViewController", sender: nil)
point += 100
}else if diferencia < 4{

performSegueWithIdentifier("GonNiceTry1ViewController", sender: nil)

point += 50


performSegueWithIdentifier("GonThirdViewController", sender: nil)




then you have to use prepareForSegue:

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {

if segue.identifier == "GonPerfectViewController"{

let vc = segue.destinationViewController as! GonPerfectViewController

vc.point = point
if segue.identifier == "GonNiceTry1ViewController"{

let vc = segue.destinationViewController as! GonNiceTry1ViewController

vc.point = point
if segue.identifier == "GonThirdViewController"{

let vc = segue.destinationViewController as! GonThirdViewController

vc.point = point


make sure you set segue identifier in every viewControllers

Sample Image

and of course you have to declare the var point also in your view controllers:

class GonPerfectViewController: UIViewController {

var point = 0

override func viewWillAppear(animated: Bool) {



you can find more info about segue here

prepare for segue programmatically with error: no segue with identifier 'value''

Since you're not using the storyboard, you must push/present the YViewController instance programatically like so,

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
let yInfo = YViewController()
yInfo.row = "hello"
self.present(yInfo, animated: true, completion: nil)

In the above code, yInfo is being presented. In case you want to push yInfo in navigation stack use pushViewController(_:animated:),

self.navigationController?.pushViewController(yInfo, animated: true)

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