Find out if Character in String is emoji?
What I stumbled upon is the difference between characters, unicode scalars and glyphs.
For example, the glyph consists of 7 unicode scalars:
- Four emoji characters: /li>
- In between each emoji is a special character, which works like character glue; see the specs for more info
Another example, the glyph consists of 2 unicode scalars:
- The regular emoji: /li>
- A skin tone modifier: /li>
Last one, the glyph 1️⃣ contains three unicode characters:
- The digit one:
1
- The variation selector
- The Combining Enclosing Keycap:
⃣
So when rendering the characters, the resulting glyphs really matter.
Swift 5.0 and above makes this process much easier and gets rid of some guesswork we needed to do. Unicode.Scalar
's new Property
type helps is determine what we're dealing with.
However, those properties only make sense when checking the other scalars within the glyph. This is why we'll be adding some convenience methods to the Character class to help us out.
For more detail, I wrote an article explaining how this works.
For Swift 5.0, this leaves you with the following result:
extension Character {
/// A simple emoji is one scalar and presented to the user as an Emoji
var isSimpleEmoji: Bool {
guard let firstScalar = unicodeScalars.first else { return false }
return firstScalar.properties.isEmoji && firstScalar.value > 0x238C
}
/// Checks if the scalars will be merged into an emoji
var isCombinedIntoEmoji: Bool { unicodeScalars.count > 1 && unicodeScalars.first?.properties.isEmoji ?? false }
var isEmoji: Bool { isSimpleEmoji || isCombinedIntoEmoji }
}
extension String {
var isSingleEmoji: Bool { count == 1 && containsEmoji }
var containsEmoji: Bool { contains { $0.isEmoji } }
var containsOnlyEmoji: Bool { !isEmpty && !contains { !$0.isEmoji } }
var emojiString: String { emojis.map { String($0) }.reduce("", +) }
var emojis: [Character] { filter { $0.isEmoji } }
var emojiScalars: [UnicodeScalar] { filter { $0.isEmoji }.flatMap { $0.unicodeScalars } }
}
Which will give you the following results:
"A̛͚̖".containsEmoji // false
"3".containsEmoji // false
"A̛͚̖▶️".unicodeScalars // [65, 795, 858, 790, 9654, 65039]
"A̛͚̖▶️".emojiScalars // [9654, 65039]
"3️⃣".isSingleEmoji // true
"3️⃣".emojiScalars // [51, 65039, 8419]
"quot;.isSingleEmoji // true
"♂️".isSingleEmoji // true
"quot;.isSingleEmoji // true
"⏰".isSingleEmoji // true
"quot;.isSingleEmoji // true
"quot;.isSingleEmoji // true
"quot;.isSingleEmoji // true
"quot;.containsOnlyEmoji // true
"quot;.containsOnlyEmoji // true
"Hello quot;.containsOnlyEmoji // false
"Hello quot;.containsEmoji // true
" Héllo quot;.emojiString // "quot;
"quot;.count // 1
" Héllœ quot;.emojiScalars // [128107, 128104, 8205, 128105, 8205, 128103, 8205, 128103]
" Héllœ quot;.emojis // ["quot;, "quot;]
" Héllœ quot;.emojis.count // 2
"quot;.isSingleEmoji // false
"quot;.containsOnlyEmoji // true
For older Swift versions, check out this gist containing my old code.
Check if String Contains an Emoji in Ruby
You can use the Emoji
Unicode property to test for Emoji using a Regexp
, something like this:
def cannot_contain_emojis
if /\p{Emoji}/ =~ my_column
errors.add(:my_column, 'Cannot include emojis')
end
end
Unicode® Technical Standard #51 "UNICODE EMOJI" contains a more sophisticated regex:
\p{RI} \p{RI}
| \p{Emoji}
( \p{EMod}
| \x{FE0F} \x{20E3}?
| [\x{E0020}-\x{E007E}]+ \x{E007F} )?
(\x{200D} \p{Emoji}
( \p{EMod}
| \x{FE0F} \x{20E3}?
| [\x{E0020}-\x{E007E}]+ \x{E007F} )?
)*
[Note: some of those properties are not implemented in Onigmo / Ruby.]
However, checking for Emojis probably not going to be enough. It is pretty clear that your text processing is somehow broken at some point. And if it is broken by an Emoji, then there is a chance it will also be broken by my name, or the name of Ruby's creator 松本 行弘, or by the completely normal English word “naïve”.
Instead of playing a game of whack-a-mole trying to detect every Emoji, mathematical symbol, Arabic letter, typographically correct punctuation mark, etc., it would be much better simply the fix the text processing.
Check if letter is emoji
It seems like those emojis are two characters long, but with split("")
you are splitting between each single character, thus none of those letters can be the emoji you are looking for.
Instead, you could try splitting between words:
for (String word : sentence.split(" ")) {
if (word.matches(emo_regex)) {
System.out.println(word);
}
}
But of course this will miss emojis that are joined to a word, or punctuation.
Alternatively, you could just use a Matcher
to find
any group
in the sentence that matches the regex.
Matcher matcher = Pattern.compile(emo_regex).matcher(sentence);
while (matcher.find()) {
System.out.println(matcher.group());
}
How to verify if a string is ONLY ONE emoji?
You can try this function:
function isOnlyOneEmoji(s) {
var EmojiPattern = /^(?:\uD83D(?:\uDD73\uFE0F?|\uDC41(?:(?:\uFE0F(?:\u200D\uD83D\uDDE8\uFE0F?)?|\u200D\uD83D\uDDE8\uFE0F?))?|[\uDDE8\uDDEF]\uFE0F?|\uDC4B(?:\uD83C[\uDFFB-\uDFFF])?|\uDD90(?:(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F))?|[\uDD96\uDC4C\uDC48\uDC49\uDC46\uDD95\uDC47\uDC4D\uDC4E\uDC4A\uDC4F\uDE4C\uDC50\uDE4F\uDC85\uDCAA\uDC42\uDC43\uDC76\uDC66\uDC67](?:\uD83C[\uDFFB-\uDFFF])?|\uDC71(?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2640\u2642]\uFE0F?))?)|\u200D(?:[\u2640\u2642]\uFE0F?)))?|\uDC68(?:(?:\uD83C(?:\uDFFB(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFC-\uDFFF]|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?|\uDFFC(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB\uDFFD-\uDFFF]|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?|\uDFFD(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF]|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?|\uDFFE(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB-\uDFFD\uDFFF]|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?|\uDFFF(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB-\uDFFE]|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?)|\u200D(?:\uD83E[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD]|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D(?:\uDC69\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|\uDC68\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?|[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92])|\u2708\uFE0F?|\u2764(?:\uFE0F\u200D\uD83D(?:\uDC8B\u200D\uD83D\uDC68|\uDC68)|\u200D\uD83D(?:\uDC8B\u200D\uD83D\uDC68|\uDC68)))))?|\uDC69(?:(?:\uD83C(?:\uDFFB(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D(?:\uDC69\uD83C[\uDFFC-\uDFFF]|\uDC68\uD83C[\uDFFC-\uDFFF])|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?|\uDFFC(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D(?:\uDC69\uD83C[\uDFFB\uDFFD-\uDFFF]|\uDC68\uD83C[\uDFFB\uDFFD-\uDFFF])|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?|\uDFFD(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D(?:\uDC69\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF]|\uDC68\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF])|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?|\uDFFE(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D(?:\uDC69\uD83C[\uDFFB-\uDFFD\uDFFF]|\uDC68\uD83C[\uDFFB-\uDFFD\uDFFF])|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?|\uDFFF(?:\u200D(?:\uD83E(?:\uDD1D\u200D\uD83D(?:\uDC69\uD83C[\uDFFB-\uDFFE]|\uDC68\uD83C[\uDFFB-\uDFFE])|[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD])|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?))?)|\u200D(?:\uD83E[\uDDB0\uDDB1\uDDB3\uDDB2\uDDAF\uDDBC\uDDBD]|\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D(?:\uDC69\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?|[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92])|\u2708\uFE0F?|\u2764(?:\uFE0F\u200D\uD83D(?:\uDC8B\u200D\uD83D[\uDC68\uDC69]|[\uDC68\uDC69])|\u200D\uD83D(?:\uDC8B\u200D\uD83D[\uDC68\uDC69]|[\uDC68\uDC69])))))?|[\uDC74\uDC75](?:\uD83C[\uDFFB-\uDFFF])?|[\uDE4D\uDE4E\uDE45\uDE46\uDC81\uDE4B\uDE47\uDC6E](?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|\uDD75(?:(?:\uFE0F(?:\u200D(?:[\u2642\u2640]\uFE0F?))?|\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|[\uDC82\uDC77](?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|\uDC78(?:\uD83C[\uDFFB-\uDFFF])?|\uDC73(?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u26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D51\uDD54\uDD55\uDD52\uDD6C\uDD66\uDDC4\uDDC5\uDD5C\uDD50\uDD56\uDD68\uDD6F\uDD5E\uDDC7\uDDC0\uDD69\uDD53\uDD6A\uDD59\uDDC6\uDD5A\uDD58\uDD63\uDD57\uDDC8\uDDC2\uDD6B\uDD6E\uDD5F-\uDD61\uDD80\uDD9E\uDD90\uDD91\uDDAA\uDDC1\uDD67\uDD5B\uDD42\uDD43\uDD64\uDDC3\uDDC9\uDDCA\uDD62\uDD44\uDDED\uDDF1\uDDBD\uDDBC\uDE82\uDDF3\uDE90\uDDE8\uDDE7\uDD47-\uDD49\uDD4E\uDD4F\uDD4D\uDD4A\uDD4B\uDD45\uDD3F\uDD4C\uDE80\uDE81\uDDFF\uDDE9\uDDF8\uDDF5\uDDF6\uDD7D\uDD7C\uDDBA\uDDE3-\uDDE6\uDD7B\uDE71-\uDE73\uDD7E\uDD7F\uDE70\uDDE2\uDE95\uDD41\uDDEE\uDE94\uDDFE\uDE93\uDDAF\uDDF0\uDDF2\uDDEA-\uDDEC\uDE78-\uDE7A\uDE91\uDE92\uDDF4\uDDF7\uDDF9-\uDDFD\uDDEF])|[\u263A\u2639\u2620\u2763\u2764]\uFE0F?|\u270B(?:\uD83C[\uDFFB-\uDFFF])?|[\u270C\u261D](?:(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F))?|\u270A(?:\uD83C[\uDFFB-\uDFFF])?|\u270D(?:(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F))?|\uD83C(?:\uDF85(?:\uD83C[\uDFFB-\uDFFF])?|\uDFC3(?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|[\uDFC7\uDFC2](?:\uD83C[\uDFFB-\uDFFF])?|\uDFCC(?:(?:\uFE0F(?:\u200D(?:[\u2642\u2640]\uFE0F?))?|\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|[\uDFC4\uDFCA](?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|\uDFCB(?:(?:\uFE0F(?:\u200D(?:[\u2642\u2640]\uFE0F?))?|\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|[\uDFF5\uDF36\uDF7D\uDFD4-\uDFD6\uDFDC-\uDFDF\uDFDB\uDFD7\uDFD8\uDFDA\uDFD9\uDFCE\uDFCD\uDF21\uDF24-\uDF2C\uDF97\uDF9F\uDF96\uDF99-\uDF9B\uDF9E\uDFF7\uDD70\uDD71\uDD7E\uDD7F\uDE02\uDE37]\uFE0F?|\uDFF4(?:(?:\u200D\u2620\uFE0F?|\uDB40\uDC67\uDB40\uDC62\uDB40(?:\uDC65\uDB40\uDC6E\uDB40\uDC67\uDB40\uDC7F|\uDC73\uDB40\uDC63\uDB40\uDC74\uDB40\uDC7F|\uDC77\uDB40\uDC6C\uDB40\uDC73\uDB40\uDC7F)))?|\uDFF3(?:(?:\uFE0F(?:\u200D\uD83C\uDF08)?|\u200D\uD83C\uDF08))?|\uDDE6\uD83C[\uDDE8-\uDDEC\uDDEE\uDDF1\uDDF2\uDDF4\uDDF6-\uDDFA\uDDFC\uDDFD\uDDFF]|\uDDE7\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEF\uDDF1-\uDDF4\uDDF6-\uDDF9\uDDFB\uDDFC\uDDFE\uDDFF]|\uDDE8\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDEE\uDDF0-\uDDF5\uDDF7\uDDFA-\uDDFF]|\uDDE9\uD83C[\uDDEA\uDDEC\uDDEF\uDDF0\uDDF2\uDDF4\uDDFF]|\uDDEA\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDED\uDDF7-\uDDFA]|\uDDEB\uD83C[\uDDEE-\uDDF0\uDDF2\uDDF4\uDDF7]|\uDDEC\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEE\uDDF1-\uDDF3\uDDF5-\uDDFA\uDDFC\uDDFE]|\uDDED\uD83C[\uDDF0\uDDF2\uDDF3\uDDF7\uDDF9\uDDFA]|\uDDEE\uD83C[\uDDE8-\uDDEA\uDDF1-\uDDF4\uDDF6-\uDDF9]|\uDDEF\uD83C[\uDDEA\uDDF2\uDDF4\uDDF5]|\uDDF0\uD83C[\uDDEA\uDDEC-\uDDEE\uDDF2\uDDF3\uDDF5\uDDF7\uDDFC\uDDFE\uDDFF]|\uDDF1\uD83C[\uDDE6-\uDDE8\uDDEE\uDDF0\uDDF7-\uDDFB\uDDFE]|\uDDF2\uD83C[\uDDE6\uDDE8-\uDDED\uDDF0-\uDDFF]|\uDDF3\uD83C[\uDDE6\uDDE8\uDDEA-\uDDEC\uDDEE\uDDF1\uDDF4\uDDF5\uDDF7\uDDFA\uDDFF]|\uDDF4\uD83C\uDDF2|\uDDF5\uD83C[\uDDE6\uDDEA-\uDDED\uDDF0-\uDDF3\uDDF7-\uDDF9\uDDFC\uDDFE]|\uDDF6\uD83C\uDDE6|\uDDF7\uD83C[\uDDEA\uDDF4\uDDF8\uDDFA\uDDFC]|\uDDF8\uD83C[\uDDE6-\uDDEA\uDDEC-\uDDF4\uDDF7-\uDDF9\uDDFB\uDDFD-\uDDFF]|\uDDF9\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDED\uDDEF-\uDDF4\uDDF7\uDDF9\uDDFB\uDDFC\uDDFF]|\uDDFA\uD83C[\uDDE6\uDDEC\uDDF2\uDDF3\uDDF8\uDDFE\uDDFF]|\uDDFB\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDEE\uDDF3\uDDFA]|\uDDFC\uD83C[\uDDEB\uDDF8]|\uDDFD\uD83C\uDDF0|\uDDFE\uD83C[\uDDEA\uDDF9]|\uDDFF\uD83C[\uDDE6\uDDF2\uDDFC]|[\uDFFB-\uDFFF\uDF38-\uDF3C\uDF37\uDF31-\uDF35\uDF3E-\uDF43\uDF47-\uDF53\uDF45\uDF46\uDF3D\uDF44\uDF30\uDF5E\uDF56\uDF57\uDF54\uDF5F\uDF55\uDF2D-\uDF2F\uDF73\uDF72\uDF7F\uDF71\uDF58-\uDF5D\uDF60\uDF62-\uDF65\uDF61\uDF66-\uDF6A\uDF82\uDF70\uDF6B-\uDF6F\uDF7C\uDF75\uDF76\uDF7E\uDF77-\uDF7B\uDF74\uDFFA\uDF0D-\uDF10\uDF0B\uDFE0-\uDFE6\uDFE8-\uDFED\uDFEF\uDFF0\uDF01\uDF03-\uDF07\uDF09\uDFA0-\uDFA2\uDFAA\uDF11-\uDF20\uDF0C\uDF00\uDF08\uDF02\uDF0A\uDF83\uDF84\uDF86-\uDF8B\uDF8D-\uDF91\uDF80\uDF81\uDFAB\uDFC6\uDFC5\uDFC0\uDFD0\uDFC8\uDFC9\uDFBE\uDFB3\uDFCF\uDFD1-\uDFD3\uDFF8\uDFA3\uDFBD\uDFBF\uDFAF\uDFB1\uDFAE\uDFB0\uDFB2\uDCCF\uDC04\uDFB4\uDFAD\uDFA8\uDF92\uDFA9\uDF93\uDFBC\uDFB5\uDFB6\uDFA4\uDFA7\uDFB7-\uDFBB\uDFA5\uDFAC\uDFEE\uDFF9\uDFE7\uDFA6\uDD8E\uDD91-\uDD9A\uDE01\uDE36\uDE2F\uDE50\uDE39\uDE1A\uDE32\uDE51\uDE38\uDE34\uDE33\uDE3A\uDE35\uDFC1\uDF8C])|\u26F7\uFE0F?|\u26F9(?:(?:\uFE0F(?:\u200D(?:[\u2642\u2640]\uFE0F?))?|\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|[\u2618\u26F0\u26E9\u2668\u26F4\u2708\u23F1\u23F2\u2600\u2601\u26C8\u2602\u26F1\u2744\u2603\u2604\u26F8\u2660\u2665\u2666\u2663\u265F\u26D1\u260E\u2328\u2709\u270F\u2712\u2702\u26CF\u2692\u2694\u2699\u2696\u26D3\u2697\u26B0\u26B1\u26A0\u2622\u2623\u2B06\u2197\u27A1\u2198\u2B07\u2199\u2B05\u2196\u2195\u2194\u21A9\u21AA\u2934\u2935\u269B\u2721\u2638\u262F\u271D\u2626\u262A\u262E\u25B6\u23ED\u23EF\u25C0\u23EE\u23F8-\u23FA\u23CF\u2640\u2642\u2695\u267E\u267B\u269C\u2611\u2714\u2716\u303D\u2733\u2734\u2747\u203C\u2049\u3030\u00A9\u00AE\u2122]\uFE0F?|[\u0023\u002A\u0030-\u0039](?:\uFE0F\u20E3|\u20E3)|[\u2139\u24C2\u3297\u3299\u25FC\u25FB\u25AA\u25AB]\uFE0F?|[\u2615\u26EA\u26F2\u26FA\u26FD\u2693\u26F5\u231B\u23F3\u231A\u23F0\u2B50\u26C5\u2614\u26A1\u26C4\u2728\u26BD\u26BE\u26F3\u267F\u26D4\u2648-\u2653\u26CE\u23E9-\u23EC\u2B55\u2705\u274C\u274E\u2795-\u2797\u27B0\u27BF\u2753-\u2755\u2757\u26AB\u26AA\u2B1B\u2B1C\u25FE\u25FD])$/;
return EmojiPattern.test(s);
}
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji("️♀️"));
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji("));
console.log(isOnlyOneEmoji(" adas"));
console.log(isOnlyOneEmoji("\/.."));
console.log(isOnlyOneEmoji(" "));
console.log(isOnlyOneEmoji("213));
console.log(isOnlyOneEmoji("$@#*///"));
console.log(isOnlyOneEmoji("XD"));
console.log(isOnlyOneEmoji("♥︎"));
console.log(isOnlyOneEmoji("✹"));
Is there a way to check if a string in JS is one single emoji?
Using this library: https://github.com/foliojs/grapheme-breaker try this:
var str = "⛹♂️";
var Grapheme = require('grapheme-splitter');
var splitter = new Grapheme();
console.log(splitter.splitGraphemes(str).length);
and the length should return 1.
Find there is an emoji in a string in python3
This works in Python 3:
def is_emoji(s):
emojis = "◼️" # add more emojis here
count = 0
for emoji in emojis:
count += s.count(emoji)
if count > 1:
return False
return bool(count)
Test:
>>> is_emoji(")
True
>>> is_emoji('◼')
True
>>> is_emoji("◼️")
False
Combine with Dunes' answer to avoid typing all emojis:
from emoji import UNICODE_EMOJI
def is_emoji(s):
count = 0
for emoji in UNICODE_EMOJI:
count += s.count(emoji)
if count > 1:
return False
return bool(count)
This is not terrible fast because UNICODE_EMOJI
contains nearly 1330 items, but it works.
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