How to parse hex values into a uint?
Try
Convert.ToUInt32(hex, 16) //Using ToUInt32 not ToUInt64, as per OP comment
How to parse hex values into Uint in c#?
You can parse the string fairly easily:
int x;
string newX = "0x00A3B43C";
if (int.TryParse(newX.Substring(2), NumberStyles.HexNumber, CultureInfo.CurrentCulture, out x))
{
Console.WriteLine("x = {0}", x); // 10728508
}
source
You do not need to convert hex notation to an int to assign it to an int, the compiler takes care of it for you. For example:
int y = 0x00A3B43C;
Console.WriteLine("y = {0}", y); // 10728508
In both cases, the console will output the value 10728508
.
How to parse long hexadecimal string into uint
Use math/big for working with numbers larger than 64 bits.
From the Int.SetString
example:
s := "d3c21bcecceda1000000"
i := new(big.Int)
i.SetString(s, 16)
fmt.Println(i)
https://play.golang.org/p/vf31ce93vA
The math/big
types also support the encoding.TextMarshaler
and fmt.Scanner
interfaces.
For example
i := new(big.Int)
fmt.Sscan("0x000000d3c21bcecceda1000000", i)
Or
i := new(big.Int)
fmt.Sscanf("0x000000d3c21bcecceda1000000", "0x%x", i)
C# convert hex string to uint array
It should be as simple as this:
string input = "0x2007A3C8,0xAE8900B8, 0x2007A3CC,0x000E5320, 0x2007A3D0,0x03E00008";
string[] strNumbers = input.Split(new[] { ',' }, StringSplitOptions.RemoveEmptyEntries);
uint[] numbers = Array.ConvertAll(strNumbers, z => Convert.ToUInt32(z.Trim(), 16));
How to convert a hex string to a uint8_t array? (C language)
You can use sscanf()
to convert 2 bytes at a time from the source string into the destination array:
#include <stdint.h>
#include <stdio.h>
size_t convert_hex(uint8_t *dest, size_t count, const char *src) {
size_t i;
int value;
for (i = 0; i < count && sscanf(src + i * 2, "%2x", &value) == 1; i++) {
dest[i] = value;
}
return i;
}
Note however that this approach may be inefficient, with a quadratic time complexity, on architectures where the standard library computes the length of the source string for each call to sscanf()
. Using an intermediary array solves this problem:
#include <stdint.h>
#include <stdio.h>
size_t convert_hex(uint8_t *dest, size_t count, const char *src) {
char buf[3];
size_t i;
int value;
for (i = 0; i < count && *src; i++) {
buf[0] = *src++;
buf[1] = '\0';
if (*src) {
buf[1] = *src++;
buf[2] = '\0';
}
if (sscanf(buf, "%x", &value) != 1)
break;
dest[i] = value;
}
return i;
}
Storing the conversion result directly into the dest
array is easy:
#include <stdint.h>
#include <stdio.h>
size_t convert_hex(uint8_t *dest, size_t count, const char *src) {
char buf[3];
size_t i;
for (i = 0; i < count && *src; i++) {
buf[0] = *src++;
buf[1] = '\0';
if (*src) {
buf[1] = *src++;
buf[2] = '\0';
}
if (sscanf(buf, "%hhx", &dest[i]) != 1)
break;
}
return i;
}
Purists may argue that %hhx
expects a pointer to an unsigned char
instead of a uint8_t
so the format should be "%"SCNx8
or "%2"SCNx8
, defined in <inttypes.h>
, but these alternatives are less readable and unnecessary as type uint8_t
is always identical to type unsigned char
on architectures where it is defined.
Get uint from hex-string in C
unsigned int h;
sscanf(code, "%x", &h);
EDIT taking account of the remark of ExP : %x
could catch the value in the string "0x41"
How to convert Hex value to acceptable uint (possibly number) using typescript
your number.toString(16)
to yield hex and parseint(hexnumber, 16)
to convert it back. I don't know if you've tried that or not. Hope it helps.
Converting a hexadecimal string to a decimal integer
In most cases, you want to parse more than one hex byte at once. In those cases, use the hex crate.
parse this into an integer
You want to use from_str_radix
. It's implemented on the integer types.
use std::i64;
fn main() {
let z = i64::from_str_radix("1f", 16);
println!("{:?}", z);
}
If your strings actually have the 0x
prefix, then you will need to skip over them. The best way to do that is via trim_start_matches
or strip_prefix
:
use std::i64;
fn main() {
let raw = "0x1f";
let without_prefix = raw.trim_start_matches("0x");
let z = i64::from_str_radix(without_prefix, 16);
println!("{:?}", z);
}
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