How to extract all strings between brackets using c#?
Here is a LINQ solution:
var result = myString.Split().Where(x => x.StartsWith("(") && x.EndsWith(")")).ToList();
Values stored in result
:
result[0] = (1)
result[1] = (0000000000)
And if you want only the numbers without the brackets use:
var result = myString.Split().Where(x => x.StartsWith("(") && x.EndsWith(")"))
.Select(x=>x.Replace("(", string.Empty).Replace(")", string.Empty))
.ToList();
Values stored in result
:
result[0] = 1
result[1] = 0000000000
How can we split string and extract the text between round brackets
You can use separate()
and set the separator as "\\s(?=\\()"
.
library(tidyr)
df %>%
separate(study_name, c("study", "reference"), sep = "\\s(?=\\()")
# # A tibble: 2 x 3
# study reference results
# <chr> <chr> <chr>
# 1 apple bannan (tcga, raw 2018) Untested
# 2 frame shift (mskk2 nature, 2000) tested
If you want to extract the text in the parentheses, using extract()
is a suitable choice.
df %>%
extract(study_name, c("study", "reference"), regex = "(.+)\\s\\((.+)\\)")
# # A tibble: 2 x 3
# study reference results
# <chr> <chr> <chr>
# 1 apple bannan tcga, raw 2018 Untested
# 2 frame shift mskk2 nature, 2000 tested
Extract text between parentheses with suffix
The key here is to use the non-greedy wildcard .*?
, otherwise everything between the first (
and the last )
would be caught:
library(stringr)
t <- 'Hui Wan (Shanghai Maritime University); Mingqiang Xu (Shanghai Chart Center, Donghai Navigation Safety Administration of MOT)*; Yingjie Xiao ( Shanghai Maritime University)'
str_extract_all(t, "(\\(.*?\\)\\*?)")[[1]] %>% str_subset("\\*$")
#> [1] "(Shanghai Chart Center, Donghai Navigation Safety Administration of MOT)*"
Created on 2021-03-03 by the reprex package (v1.0.0)
You can use the rev()
function if you want to reverse the order and get it right to left.
This is far less elegant than I would like it but unexpectedly "(\\(.*?\\)\\*)"
is not non-greedy, so I had to detect it at the end of the string. You can add %>% str_remove_all("\\*$")
if you want to discard the star in the end string.
extracting text inside brackets & text outside with regex
You may use a [^][]+
pattern (negated character class) to match 1 or more chars other than [
and ]
:
\[(?<colors>[^][]+)](?<text>[^][]+)
See the regex demo. Note that in the demo, I added \n
to the negated character classes as the test is done on a single multiline string, if you test against multiple separate, standalone strings, you do not need it.
In some regex engines, you have to escape [
or ]
or both inside a character class, as in Java, Ruby or Swift/Objective-C (Boost library), so use
\[(?<colors>[^\]\[]+)](?<text>[^\]\[]+)
If text
group may be empty, replace (?<text>[^\]\[]+)
with (?<text>[^\]\[]*)
, *
will match 0 or more occurrences.
Get text between two rounded brackets
console.log(
"This is (my) simple text".match(/\(([^)]+)\)/)[1]
);
Regex to extract text between brackets
Try this:
Insurance.*\[(\d+)\]
Or if you want to match it between the 2x "Insurance" words
Insurance.*\[(\d+)\][\s\S]+?Insurance
Demo here.
Where
Insurance
- Match the starting word "Insurance".*
- Match any character\[
- Match the opening bracket(\d+)
- Capture the numerical value inside brackets\]
- Match the closing bracket[\s\S]+?
- Match any character (including newlines) in a non-greedy way so that it wouldn't span across multiple "Insurance" wordsInsurance
- Match the ending word "Insurance"
How to extract text inside the brackets in R?
You can use str_extract_all
from the stringr
package with this regex pattern:
stringr::str_extract_all(string,
"\\(\\w+([[:punct:]]{1}|[[:blank:]]{1})[[:digit:]]+\\)")
# [[1]]
# [1] "(antonio.2018)" "(giovanni,2018)" "(libero 2019)"
A small description of the regex:
\\w
will match any word-character+
means that it has to be matched at least once[[:punct:]]
will match any punctuation character{1}
will exactly one appearance(....|....)
indicates one pattern OR the other has to be met[[:blank:]]
means any whitespace must occur[[:digit:]]
means any digit must occur\\(
braces have to be exited.
Extract text between parentheses from string
Split() cuts a string into an array of parts separated by a string (not a regexp). You are looking for the parts of an input string that are (made of) a sequence of digits. So you need a Regexp that specifies a sequence of digits: \d+.
>> strtoSplit = "Hello everyone! (27082015) What is your name? (123456789)"
>> Set r = New RegExp
>> r.Global = True
>> r.Pattern = "\d+"
>> For Each m In r.Execute(strtoSplit)
>> WScript.Echo m.Value
>> Next
>>
27082015
123456789
On seconded thought:
I should have understood from the start that you are interested in the parts 'between the parentheses'. So the pattern needs to change and we have to access a group:
>> Set r = New RegExp
>> r.Global = True
>> r.Pattern = "\(([^)]+)\)"
>> For Each m In r.Execute(strtoSplit)
>> WScript.Echo m.SubMatches(0)
>> Next
>>
27082015
123456789
Regular expression to extract text between square brackets
You can use the following regex globally:
\[(.*?)\]
Explanation:
\[
:[
is a meta char and needs to be escaped if you want to match it literally.(.*?)
: match everything in a non-greedy way and capture it.\]
:]
is a meta char and needs to be escaped if you want to match it literally.
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