Are multiple conditions allowed in a for loop?
The condition
i < p, j < q
is allowed but probably isn't what was intended as it discards the result of the first expression and returns the result of j < q
only. The comma operator evaluates the expression on the left of the comma, discards it then evaluates the expression on the right and returns it.
If you want to test for multiple conditions use the logical AND operator &&
instead
i < p && j < q
Multiple conditions in a C 'for' loop
The comma operator evaluates all its operands and yields the value of the last one. So basically whichever condition you write first, it will be disregarded, and the second one will be significant only.
for (i = 0; j >= 0, i <= 5; i++)
is thus equivalent with
for (i = 0; i <= 5; i++)
which may or may not be what the author of the code intended, depending on his intents - I hope this is not production code, because if the programmer having written this wanted to express an AND relation between the conditions, then this is incorrect and the &&
operator should have been used instead.
Giving multiple conditions in for loop in Java
You can also use "or" operator,
for( int i = 0 ; i < 100 || someOtherCondition() ; i++ ) {
...
}
Multiple conditions in for-loop
Your break
statement indentation is not correct. The code is always breaking the loop at the first break
.
The code should be like this:
import pandas as pd
z={'speed':[2.2, 2.74, 5.1, 9.1, 0.5]}
data=pd.DataFrame(data=z)
found = 0
for k in range(len(data['speed']) - 1, 0, -1):
if (data['speed'][k]<5 and data['speed'][k-1]<5):
print(k)
found = 1
break
if found == 0:
for k in range(len(data['speed']) - 1, -1, -1):
if data['speed'][k]<5:
print(k)
break
Multiple conditions in for loop
Since a for
loop is equivalent to a while
loop plus a couple of statements, and CoffeeScript offers only one kind of for
loop, use a while
loop. If you’re trying to get specific JavaScript output, you should probably not be using CoffeeScript.
Of course, there is always
`for(k=1; k < 120 && myThing.someValue > 1234; k++) {`
do myThing.action
`}`
Avoid.
multiple conditions Under the 'for' loop [duplicate]
for(int i=0;i>1&&i<4; i++ ) {
^------^ expression
For loops execute until the expression is false, and then stop executing. This expression is immediately false (because 0>1
is false), so it immediately stops executing. It doesn't "wait and see" if the expression becomes true again.
If you only want the loop to execute for i>1&&i<4
:
for(int i = 2; i<4; i++ ) {
How to loop in python with multiple conditions [duplicate]
Your loop should continue while n < 0
or n > 9
:
while n < 0 or n > 9:
...
The negation of this condition, by de Morgan's laws, is probably what you were aiming for:
while not (0 <= n <= 9):
...
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