How to Have All the Inputs on the Same Line C++

How to take multiple inputs in the same line in C++?

You can do this simply by cascading the the cin operator. If you write a code in this way:

int a,b;
cout << "Enter value of a" << endl;
cin >> a;
cout << "Enter value of b" << endl;
cin >> b;

then the program execution would be in this way:

Enter value of a
10
Enter value of b
20

But to do this in a single line, you can write the code in this way:

cout << "Enter the values of a and b" << endl;
cin >> a >> b; //cascading the cin operator

The program execution now goes thus:

Enter the values of a and b
10 20

If you enter both values this way (separating them with a space), then it works the way you want it to - being in the same line.

Also, in the first snippet, if you remove the endl keyword, you can also have it all in one line but I don't think that's what you want.

Also see: CASCADING OF I/O OPERATORS | easyprograming.

How to have all the inputs on the same line C++

The behavior depends on the input provided by the user.

Your code works as you want, if the user would enter everything (e.g.14:53) on the same line and press enter only at the end:

Demo 1

Now you can have a better control, if you read a string and then interpret its content, for example as here:

string t; 
cout << "\n\tTime: "; 
cin >> t;
stringstream sst(t);
int timeHours, timeMinutes;
char c; 
sst>>timeHours>>c>>timeMinutes;

Demo 2

How to get multiple inputs in one line in C?

You are reading the number of inputs and then repeatedly (in a loop) read each input, eg:

#include <stdio.h>
#include <stdlib.h>

int main(int ac, char **av)
{
        int numInputs;
        int *input;

        printf("Total number of inputs: ");
        scanf("%d", &numInputs);

        input = malloc(numInputs * sizeof(int));

        for (int i=0; i < numInputs; i++)
        {
                printf("Input #%d: ", i+1);
                scanf("%d", &input[i]);
        }

        // Do Stuff, for example print them:
        for (int i=0; i < numInputs; i++)
        {
                printf("Input #%d = %d\n", i+1, input[i]);
        }

        free(input);
}

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